Answer: 64.6 mmHg
Explanation:
Given that:
Volume of gas V = 3.47L
(since 1 liter = 1dm3
3.47L = 3.47dm3)
Temperature T = 85.0°C
Convert Celsius to Kelvin
(85.0°C + 273 = 358K)
Pressure P = ?
Number of moles of gas N = 0.100 mole
Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 3.47dm3 = 0.10 x (0.0082 atm dm3 K-1 mol-1 x 358K)
p x 3.47dm3 = 0.29 atm dm3
p = (0.29 atm dm3 / 3.47 dm3)
p = 0.085 atm
Recall that pressure of the gas is required in mm hg, so convert 0.085 atm to mm Hg
If 1 atm = 760 mm Hg
0.085atm = 0.085 x 760
= 64.6 mm Hg
Thus, the pressure of the gas is 64.6 mm hg
Answer:
all 4 of the middle ones are part of the nucleus
Answer:
V = 48.5 L
Explanation:
Converting °C to K and kPa to atm
T = 25.0°C + 273.15 = 298.15 K
P = 61.3 kPa × (1 atm / 101.325 kPa) = 0.60498 atm
Calculating the volume of gas
V = nRT / P
V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm
V = 48.5 L