Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Option C is correct option.
Step-by-step explanation:
We need to find the solution of 
The given inequality becomes undefined when x = 1 because the denomiator is: 1-x and if x = 1 then it becomes 1-1 = 0 and anything divided by zero is undefined.
So, all values other than 1 are included in the solution of the given inequality.
So, solution is: x<1 or x>1 but x≠1
So, Option C is correct because all numbers are included in number line except 1. An unfilled circle on 1 shows that it is not included in the solution. Rest of numbers are included.
Option C is correct option.
Keywords: Solving inequalities
Learn more about Solving inequalities at:
#learnwithBrainly
Answer:
308
Step-by-step explanation:
Well you have to subtract 14056 from 32713 and the answer will be 18657
You mean
the linear equations, 5x-y+1=0,4x-y+1=0
the slopes are 5 and 4 respectively.
it is clear that slope of first equation is greater that is it has a steeper graph therefore it Will always be greater than the other for x > 1
the same can be done by calculus; differentiation.
note y=5x+1 is always greater than y=4x+1 for all x>1