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RUDIKE [14]
3 years ago
10

How would I find the day of my next birthday without using a calendar and maybe a linear sequence.

Mathematics
1 answer:
ryzh [129]3 years ago
7 0
What was ur bday last year and then add one day onto it. So say last year it was Tuesday then this year it would be Wednesday
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What is 4sqrt7^3 in exponential form?
katrin [286]

Answer:

\boxed{7^{\frac{3}{2} } \times 4}

Step-by-step explanation:

4 (\sqrt{7} )^3

Square root can be written as a power.

4(7^{\frac{1}{2} })^3

Multiply the exponents.

4(7^{\frac{3}{2} })

7 0
3 years ago
If f(x)=3x+1 then f(a+h)-f(a)
Varvara68 [4.7K]
F(x) = 3x+1
put x = a+h
f(a+h)  = 3(a+h) + 1
f(a+h) = 3a + 3h + 1
put x = a
f(a) = 3a + 1
f(a+h)-f(a) = 3a + 3h + 1 -(3a+1)
f(a+h)-f(a) = 3a +3h + 1 - 3a -1
f(a+h)-f(a) = 3h
7 0
3 years ago
Hey Guys! I need some help. This is the question... Sara travels often for her job. The miles she traveled for the last seven wo
Schach [20]

Using the median concept, it is found that the interquartile range of Sara's daily miles is of 21 miles.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the quartiles.

The ordered data-set is given as follows:

65, 72, 86, 88, 91, 93, 97

There are 7 elements, hence the median is the 4th element, of 88. Then:

  • The first half is 65, 72, 86.
  • The second half is 91, 93, 97.

Since the quartiles are the medians of each half, the have that:

  • The first quartile is of 72 miles.
  • The third quartile is of 93 miles.
  • The interquartile range is of 93 - 72 = 21 miles.

More can be learned about the median of a data-set at brainly.com/question/3876456

#SPJ1

4 0
2 years ago
what is the completely factored form of t^4 − 16? (t^2 4)(t^2 − 4) (t^2 4)(t 2)(t − 2) (t^2 4)(t − 2)(t − 2) (t 2)(t 2)(t 2)(t −
Eva8 [605]
Use:a^2-b^2=(a-b)(a+b)\\\\t^4-16=(t^2)^2-4^2=(t^2-4)(t^2+4)=(t^2-2^2)(t^2+4)=(t-2)(t+2)(t^2+4)
7 0
3 years ago
Help with this pleaseeee​
ELEN [110]

Answer:

(- 3, 37) and (- \frac{5}{2}, \frac{63}{2} )

Step-by-step explanation:

Given the 2 equations

2x² - y + 19 = 0 → (1)

y + 11x = 4 → (2) ← subtract 11x from both sides

y = 4 - 11x → (3)

Substitute y = 4 - 11x into (1)

2x² - (4 - 11x) + 19 = 0

2x² - 4 + 11x + 19 = 0

2x² + 11x + 15 = 0 ← in standard form

(2x + 5)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - \frac{5}{2}

x + 3 = 0 ⇒ x = - 3

Substitute these values into (3) for corresponding values of y

x = - \frac{5}{2} : y = 4 + \frac{55}{2} = \frac{63}{2} ⇒ (- \frac{5}{2}, \frac{63}{2} )

x = - 3 : y = 4 + 33 = 37 ⇒ (- 3, 37 )

4 0
3 years ago
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