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RUDIKE [14]
3 years ago
10

How would I find the day of my next birthday without using a calendar and maybe a linear sequence.

Mathematics
1 answer:
ryzh [129]3 years ago
7 0
What was ur bday last year and then add one day onto it. So say last year it was Tuesday then this year it would be Wednesday
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What is the value of the expression 7^−3<br><br> A. 1/343<br> B.−21<br> C.343<br> D.1/343
WINSTONCH [101]

Answer: A. \frac{1}{343}


Step-by-step explanation:

First, apply exponent rule.

=\frac{1}{7^3}

7^3=7*7*7=343

=\frac{1}{343}

Hope this helps!

Thank you for posting your question.

-Charlie

4 0
3 years ago
Double the quotient of 3 and 6​
Hitman42 [59]

\huge{\boxed{1}}

This statement can be represented as 2*\frac{3}{6}, since the quotient is the answer to a division problem.

Divide. 2*\frac{1}{2}

Multiply. 2*\frac{1}{2}=\frac{2}{1}*\frac{1}{2}=\frac{2*1}{1*2}=\frac{2}{2}

Simplify.  When the numerator and denominator are the same, the fraction is equal to 1. \frac{2}{2}=1

5 0
3 years ago
The figure below shows rectangle ABCD.
kipiarov [429]

Answer: We can find out the missing statement with help of below explanation.

Step-by-step explanation:

We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)

We have to prove: Diagonals AC and BD bisect each other.

In triangles, AED and BEC.

\angle ADB \cong \angle CBD ( By alternative angle theorem)

AD\cong BC ( Because ABCD is a rectangle)

\angle CAD\cong \angle ACB  ( By alternative angle theorem)

By ASA postulate,\triangle AED\cong \triangle BEC

By CPCTC, BE\cong ED and CE\cong EA

⇒ BE= ED and CE=EA

By the definition of bisector, AC and BD bisect each other.


4 0
3 years ago
Read 2 more answers
Determine whether each quadrilateral is a parallelogram. Write yes or no. If yes, give a reason for your answer. ​
emmasim [6.3K]

Answer:

yes

Step-by-step explanation:

All of the opposite sides are parallel  to each other.  

6 0
3 years ago
4k + 15 greater than -2k + 3
ioda

Answer:

k>-2

Step-by-step explanation:

4k+15>-2k+3

4k-(-2k)+15>3

4k+2k+15>3

6k+15>3

6k>3-15

6k>-12

k>-12/6

k>-2

8 0
3 years ago
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