Given:
The line passing through (-2,5) and (2,p) has a gradient of
.
To find:
The value of p.
Solution:
If a line passes through two points, then the slope of the line is:
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
The line passing through (-2,5) and (2,p). So, the slope of the line is:
![m=\dfrac{p-5}{2-(-2)}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bp-5%7D%7B2-%28-2%29%7D)
![m=\dfrac{p-5}{2+2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bp-5%7D%7B2%2B2%7D)
![m=\dfrac{p-5}{4}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bp-5%7D%7B4%7D)
It is given that the gradient or slope of the line is
.
![\dfrac{p-5}{4}=-\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp-5%7D%7B4%7D%3D-%5Cdfrac%7B1%7D%7B2%7D)
On cross multiplication, we get
![2(p-5)=-4(1)](https://tex.z-dn.net/?f=2%28p-5%29%3D-4%281%29)
![2p-10=-4](https://tex.z-dn.net/?f=2p-10%3D-4)
![2p=-4+10](https://tex.z-dn.net/?f=2p%3D-4%2B10)
![2p=6](https://tex.z-dn.net/?f=2p%3D6)
Divide both sides by 2.
![p=3](https://tex.z-dn.net/?f=p%3D3)
Therefore, the value of p is 3.
Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i
The additive inverse of the complex number a + bi is -(a+bi) = -a - bi
In this case, a = -8 and b = 3i
a + bi = -8 + 3i
additive inverse is: -(-8+3i) = +8 - 3i
The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.
</span>
Answer:
We know that in a triangle, if two angles have equal measures, then the sides opposite to them are equal in length. Thus, the length of side AB is 6 units
I did the work and it's D. i believe
Answer:
huh
Step-by-step explanation: