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exis [7]
3 years ago
7

Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I': Hexagon DEFGHI and Hexagon D prime E

prime F prime G prime H prime I prime on the coordinate plane with ordered pairs at D 2, 5, at E 5, 5, at F 6, 3, at G 5, 1, at H 2, 1, at I 1, 3, at D prime negative 6, negative 2, at E prime negative 3, negative 2, at F prime negative 2, negative 4, at G prime negative 3, negative 6, at H prime negative 6, negative 6, at I prime negative 7, negative 4 Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'? (x, y)→(x − 8, y − 7) (x, y)→(x − 7, x − 8) (x, y)→(x − 4, x − 5) (x, y)→(x − 5, y − 4)
Mathematics
2 answers:
MatroZZZ [7]3 years ago
4 0
<span>(x, y)→(x − 8, y − 7) is the correct translation. Take point D for example. The coordinate of D is (2, 5). The coordinate of D' (after translation) is (-6, -2). Since 2-8=-6, 5-7=-2, only the first choice is correct. You can also try other points and see why only this is the right translation.</span>
ad-work [718]3 years ago
3 0

Answer:

(x, y)→(x − 8, y − 7)

Step-by-step explanation:

If we take the hexagon DEFGHI coordinates and apply the rule (x, y)→(x − 8, y − 7) we get:

D (2, 5) → (2 - 8, 5 - 7) = (-6, -2) which corresponds to point D'

E (5, 5) → (5 - 8, 5 - 7) = (-3, -2) which corresponds to point E'

F (6, 3) → (6 - 8, 3 - 7) = (-2, -4) which corresponds to point F'

G (5, 1) → (5 - 8, 1 - 7) = (-3, -6) which corresponds to point G'

H (2, 1) → (2 - 8, 1 - 7) = (-6, -6) which corresponds to point H'

I (1, 3) → (1 - 8, 3 - 7) = (-7, -4) which corresponds to point I'

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Step-by-step explanation:

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2 years ago
Clarissa helps her mom put the 200-Newton lawn mower in the back of her mom’s truck. They lift the mower up from the ground to t
mihalych1998 [28]

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220 N * m or 220 J

Step-by-step explanation:

We have that the work formula would be the applied force multiplied by the distance traveled, that is:

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6 0
3 years ago
StartLayout Enlarged left-brace 1st row x² + y² = 25 2nd row 2x + y = 25 EndLayout 0, –5) and (–5, 5) (0, –5) and (5, –15) (0, –
Verdich [7]

Answer:

The line does not intersect the curve

Step-by-step explanation:

Assuming that we are looking for the points of intersection of

{x}^{2}  +  {y}^{2}  = 25

and

2x + y = 25

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y = 25 - 2x

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{x}^{2}  +  {(25 -2 x)}^{2}  = 25

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{x}^{2}  + 625 - 100x + 4 {x}^{2}  = 25

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5 {x}^{2}  - 100x + 600 = 0

Divide through by 5

{x}^{2}  - 20x + 120 = 0

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3 0
3 years ago
Read 2 more answers
For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
We know that the angles of a triangle sum to 180°.  For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180

Combining like terms,
16x+20=180

Subtracting 20 from both sides:
16x=160

Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.

For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180

Combining like terms, 
20x-20=180

Adding 20 to both sides:
20x=200

Dividing both sides by 20:
x=10

This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.

Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
5 0
3 years ago
Read 2 more answers
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