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9966 [12]
1 year ago
5

Simplify 2√2-√3 --------------- √2+√3

Mathematics
1 answer:
serious [3.7K]1 year ago
6 0

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

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Hey! Apologies that I can’t make this look nice because I’m on mobile.

To simplify this, we can multiply the denominator by its conjugate. For a imaginary function (a+bi), its conjugate would be (a-bi), so we can apply that here to multiply both sides by (2-i)/(2-i). This works because it simplifies to one. Then, we have our fraction as 4*(2-i)/((2-i)(2+i))=(8-4i)/(4-i^2)=(8-4i)/5

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Step-by-step explanation:

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