Okay, so this is a multi-step problem. If there are 82 students, and the cost was $3.75 PER student, we would multiply 3.75 times 82 to get 307.50, and now we would subtract the total amount of sales, ($2,071.50), MINUS the ticket sales made by students, ($307.50). So 2,071.50 - <span>307.50 = 1,764.
So this means that they made $1,764 in ticket sales from ADULTS. Now to find out how many adults were THERE, (or the amount of adult tickets that were sold), we will divide 1,764 divided by the price of each adult ticket, ($10.50), which will be 1,764 divided by 10.50 = 168.
168 adult tickets were sold.
I hope I helped! =D
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Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(3,8)(-7,11)
d = sqrt (-7 - 3)^2 + (11 - 8)^2
d = sqrt (-10^2) + (3^2)
d = sqrt (100 + 9)
d = sqrt 109
d = 10.44
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mid-point formula : ((x1 + x2) / 2 , (y1 + y2) / 2)
(-9,5)(21,-7)
midpoint = ((-9 + 21)/2 , (5 + (-7)/2)
= ((12/2) , (-2,2))
= (6, -1) <==
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(-8,7)(-9,11)
midpoint = ((-8 + (-9) / 2, (7 + 11)/2 )
= (-17/2, 18/2)
= (-8.5, 9) <==
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(8,y)(-11,6).....midpoint = (-1.5/5)
midpoint = ((8 + (-11)/2, (y + 6)/2)
= (-3/2), (4 + 6)/2
= (-1.5,5)
y = 4 <==
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slope = (y2 - y1) / (x2 - x1)
(3,-6)(6,12)
slope = (12 - (-6) / (6 - 3) = (12 + 6) / 3 = 18/3 = 6 <==
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(x,10)(-4,8)...slope = 2/3
y = mx + b
slope(m) = 2/3
(-4,8)...x = -4 and y = 8
sub and find b
8 = 2/3(-4) + b
8 = -8/3 + b
8 + 8/3 = b
24/3 + 8/3 = b
32/3 = b
equation is : y = 2/3x + 32/3 or 3y = 2x + 32
when y = 10
3(10) = 2x + 32
30 - 32 = 2x
-2 = 2x
-2/2 = x
-1 = x <===
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(9,0)(3,y)...slope = 1/2
y = mx + b
slope(m) = 1/2
(9,0)...x = 9 and y = 0
sub and find b
0 = 1/2(9) + b
0 = 9/2 + b
-9/2 = b
equation is : y = 1/2x - 9/2 or 2y = x - 9
sub in 3 for x and solve for y
2y = 3 - 9
2y = -6
y = -6/2
y = -3 <==
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(8,7)(11,7)...notice how the y values are the same. This means it is a horizontal line. A horizontal line has a slope of 0.
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sorry...not too good with the picture graphs
Answer:
D got it right on my quiz
Step-by-step explanation:
:)
The incorrect answer is -10 1/2
So your answer will be
Answer = -10 1/2
Linear mathematical models describe real world applications with the use lines. For instance, a car going 50 mph, has traveled a distance represented by y=50x, where x is time in hours and y is miles. The equation and graph can be used to make predictions.