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wel
3 years ago
12

What is the value of the median ? 1. 8 2. 4 3. 6 4. -4

Mathematics
1 answer:
mart [117]3 years ago
4 0
The value of the median is going to be 6
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Please helppp with this math question <333
Naya [18.7K]

Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

5 0
2 years ago
What is the basic unit for length in the si unit
klio [65]

Answer: i think its metre

8 0
3 years ago
Can someone help me plz??
Irina-Kira [14]
It's hard to read your picture

But if your equation is
(-3)^2 + (-2)^3

then its:

-3*-3 + -2*-2*-2 = -9 - 8 = -17
8 0
3 years ago
Read 2 more answers
I need help, thank you
natali 33 [55]
Plot it on point (-2,-1)
7 0
3 years ago
Read 2 more answers
Nick bought a new car.
ira [324]

Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:

A(t) = A(0)(0.88)^t.

It halves in value at t years, for which A(t) = 0.5A(0), hence:

A(t) = A(0)(0.88)^t

0.5A(0) = A(0)(0.88)^t

(0.88)^t = 0.5

\log{(0.88)^t} = \log{0.5}

t\log{0.88} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.88}}

t = 5.42.

It takes 5.42 years for the car to halve in value.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

9 0
1 year ago
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