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2 years ago

A boy is standing next to a radio. As he moves away from the radio, which would MOST LIKELY occur?

Mathematics

2 answers:

Alexxandr [17]2 years ago

5 0

The last one im pretty sure

Olenka [21]2 years ago

3 0

Answer: C

Step-by-step explanation:

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And Matthew ran a lemonade stand on Saturday they agreed that Matthew would get 60% of the profit because a lemonade stand was h

VladimirAG [237]

Matthew makes $15 money .

Step-by-step explanation:

Total profit = $25
Matthew gets 60% of the profit.

Therefore, the Matthew would get 60% of 25.

⇒ (60/100) $\times$ 25

⇒ 0.6 $\times$ 25

⇒ $15

6 0

2 years ago

A train left a station a station at noon going 40mph. A second train left at 3 p.m. going 60mph. At what time will the second tr

Sati [7]

Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.

But the time traveled will be different .

Let us say the two trains meet at time t ,

Distance = speed * time

Distance traveled by first train = 40 t

Since second train is leaving after three hours , so

Distance traveled by second train = 60(t-3)

As discussed earlier, distance traveled will be same, so

$40t =60(t-3)$

distributing 60 over t-3

$40t =60t-180$

$60t -40t=180$

$20t =180$

$t =180/20$

t=9

So the second train will meet the first at 9 p.m.

5 0

2 years ago

Read 2 more answers

Unemployment is the ratio of

Kaylis [27]

Answer:

I think it is A.

Step-by-step explanation:

happy to help

5 0

3 years ago

Read 2 more answers

An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e

uranmaximum [27]

Answer:

The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938

Step-by-step explanation:

Given:

Here Section 1 students = 20

Section 2 students = 30

Here there are 15 graded exam papers.

(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070

(b) Here if x is the number of students copies of section 2 out of 15 exam papers.

here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15

Then,

Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798

(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)

so,

Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938

Note : Here the given distribution is Hyper-geometric distribution

where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.

7 0

3 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

Romashka [77]

Answer:

Shelter A

Step-by-step explanation:

For Shelter A: the whiskers range from 8 to 30

so, the minimum weight of Shelter A is 8 pounds.

For For Shelter B: the whiskers range from 10 to 28

so, the minimum weight of Shelter B is 10 pounds.

Which animal shelter has the dog that weighs the least?

The answer is: Shelter A

Note: whiskers are plotted are from the minimum to Q1 and from Q2 to the max.

See the attached figure.

4 0

3 years ago

Read 2 more answers