Jk,kl, and lj are all tangent to circle o, ja=13,al=7, and ck=10 what is the perimeter of angle JKL
1 answer:
see the picture attached to better understand the problem
we know that
two tangent segments drawn from the same exterior point are congruent
so
JA=JB ,
LA=LC,
KC=KB
JA=13 units
LA=7 units
kC=10 units
hence
perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units
therefore
the answer is
the perimeter of triangle JKL is 60 units
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Answer:
Option (3). 120° will be the answer.
Step-by-step explanation:
By using the theorem of secants intersecting externally,
Measure of angle formed by two secants, from a point outside the circle is half the difference of the measures of the intercepted arcs.
m∠C =
36° =
72° = °
= 72 + 48
= 120°
Therefore, Option (3) is the answer.