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ki77a [65]
2 years ago
12

Find the altitude of this equilateral triangle - geometry

Mathematics
1 answer:
Bond [772]2 years ago
7 0

Answer:

4√3.

Step-by-step explanation:

If the height is h then

tan 60 = h / (1/2*8)

tan 60 = h/4

h = 4 tan 60

   = 4 * √3.

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Serga [27]

Answer:

15m+80 would be the correct equation

3 0
3 years ago
Read 2 more answers
Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio
adoni [48]

Answer:

a : b = 4 : 3

Step-by-step explanation:

(mark as brainlist answer)

According to the given condition is the question :

Two numbers a and b are such that the sum of 5% of a and 4% of b is two-third of the sum of 6% of a and 8% of b

⇒ (5% of a) + (4% of b) = (2/3) × [(6% of a) + (8% of b)

⇒ 0.05a + 0.04b = 2/3 × (0.06a + 0.08b)

⇒ 0.15a + 0.12b = 0.12a + 0.16b

⇒ 0.03a = 0.04b

⇒ a/b = 4/3

⇒ a : b = 4 : 3

8 0
3 years ago
1) (1 Point) : If-18 - x=9, then -5 +6x = ?
TiliK225 [7]
-167, because if you solve -18-x=9, x will be equal to -27. When you put -27 in place of the x in -5+6x, you get -167. Have a nice day!
3 0
2 years ago
Find the product of 543.1187 and 100 A. 5.431187 B. 54,311.87 C. 5,431.187 D. 54.31187 Can someone also explain how they came up
Katyanochek1 [597]
543.1187\times100=\boxed{54311.87}

When you're multiplying by a power of 10 such as 100, the decimal point moves two places to the right. Note that this corresponds with the number of zeroes in 100. Of course our number is going to get bigger, not smaller, which means we'd have to be going right. If we multiplied by something like 0.001, we'd also be going two places, just going smaller and to the left.
7 0
2 years ago
Read 2 more answers
Solve for y x=y^2+4y
Lorico [155]
x=y^2+4y\\ y^2+4y-x=0\\\Delta=4^2-4\cdot1\cdot(-x)=16+4x\\\\
1.\ \Delta0\\
\sqrt{\Delta}=\sqrt{16+4x}=\sqrt{4(4+x)}=2\sqrt{x+4}\\
y_1=\frac{-4-2\sqrt{x+4}}{2\cdot1}=-2-\sqrt{x+4}\\
y_2=\frac{-4+2\sqrt{x+4}}{2\cdot1}=-2+\sqrt{x+4}\\

-----------------------------------------------------

x=y^2+4y\\ y^2+4y-x=0\\
y^2+4y+4-4-x=0\\
(y+2)^2=x+4\\
y+2=\sqrt{x+4} \vee y+2=-\sqrt{x+4}\\
y=-2+\sqrt{x+4} \vee y=-2-\sqrt{x+4}\\

4 0
3 years ago
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