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s2008m [1.1K]
3 years ago
9

1.9 x (1/4) answer as a fraction

Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

19/40 1.9x0.25=0.475= 19/40

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Factor completely 4x2 + 16x.
Andrew [12]
First factor out the gcf.

4x(x+4)

The inner binomial cannot be factored so that is the final answer.
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3 years ago
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What is 0.65 as a percentage
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65 percent thats your answer when you convert the number easy as that<span />
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Dana can travel 9 miles in her rowboat in 6 hours against the current. With the current, it takes 4 hours to row the same distan
taurus [48]

Answer: The equations are

6x - 6y = 9

4x + 4y = 9

Step-by-step explanation:

Let x represent the speed of the row boat in still water.

Let y represent the speed of the current.

Dana can travel 9 miles in her rowboat in 6 hours against the current. This means that the total speed at which she travelled is

(x - y) miles per hour.

Distance = speed × time

Distance travelled against the current is expressed as

9 = 6(x - y)

6x - 6y = 9

With the current, it takes 4 hours to row the same distance. This means that the total speed at which she travelled is

(x + y) miles per hour.

Distance travelled with the current is expressed as

9 = 4(x + y)

4x + 4y = 9

7 0
3 years ago
In an automobile parts factory, for every 175 carburetors 3 are found to be defective. At that rate how many carbureatots out of
Furkat [3]

Answer:

At the same  rate 18  carburetors out of 1,050 could be expected to be detective.

Step-by-step explanation:

The number of carburetors tested = 175

Defective pieces out o f 175 = 3

So, ratio of defected to tested =    3   :    175

Now, the number of carburetors tested in second batch = 1,050

Here, let the defective pieces = m

So, by the Ratio of Proportion,

\frac{3}{175}  = \frac{m}{1050}

or, m = \frac{1050  \times 3}{175}  = 18

⇒ m = 18

Hence, at the same  rate 18  carburetors out of 1,050 could be expected to be detective.

8 0
3 years ago
. Write the following expression in factored form using the greatest common factor.<br> 50a3 + 10a2
Tanya [424]

The factors of  50a³  are  1,  2,  5,  10,  25,  50,
   and their products with a, a² and a³ .

The factors of  10a²  are  1,  2,  5,  10,
    and their products with 'a' and a² .

Their common factors are  1, 2, 5, 10,
       and their products with 'a' and a².

Their greatest common factor is  10a² .

(Another way to spot it, easily, is to remember this helpful factoid:

                 If the smaller number is a factor of the larger number,
                 then the smaller number is their greatest common factor.

Using the greatest common factor, then . . .

           50a³ + 10a²  =     10a²(5a + 1) .

3 0
3 years ago
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