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schepotkina [342]
2 years ago
5

A concave mirror light, whereas a concave lens light.

Physics
1 answer:
Pachacha [2.7K]2 years ago
5 0

Answer: Answer.

1)Concave lens is transparent whereas the concave mirror is opaque. 2)concave mirrors cause reflection whereas concave lense cause refraction of light.

3)concave mirror forms both real, inverted images of various sizes and virtual, erect, and enlarged images whereas a concave lens form only virtual images.

Explanation:

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A portion of the atmosphere that becomes warmer than surrounding air will ____.
earnstyle [38]
<span>A portion of the atmosphere that becomes warmer than surrounding air will expand and rise. The warmer atmosphere the more space between the molecules. Therefore, warmer atmosphere </span><span>expands to allow more space for the molecules. Cool air on the other hand, contracts because the molecules in cool air need less space.</span>
3 0
3 years ago
Two point charges q and 4q are at x=0 and x=l, respectively, and free to move. a third charge is placed so that the entire three
tatuchka [14]

Explanation :

It is given that, q and 4q are placed at a distance of l.

Let x is the distance where third charge is placed so that the entire three charge system is in static equilibrium.

Equilibrium means the net force acting on the system of charges is equal to zero. Let Q is the third charge.

So, \dfrac{kqQ}{x^2}=\dfrac{k(Q)(4q)}{(l-x)^2}

On solving,

x=\dfrac{l}{3}

For magnitude :

\dfrac{kqQ}{(l/3)^2}=\dfrac{kq4q}{l^2}

using x=\dfrac{l}{3}

Q=\dfrac{4q}{9}

So, a charge of -4q/9 is at a distance of l/3 is placed. It is placed to the right of  +q.

8 0
4 years ago
Why is it less air pressure up in the sky and why does it affect our ears
IgorLugansk [536]

Answer:

When you in a airplane you are in high altitude and thats where air density drops. Thats where ear pops come from.

Explanation:

8 0
2 years ago
A 500g air-track glider attached to a spring with spring constant 10 N/m is sitting at rest on a frictionless air track. A 250 g
d1i1m1o1n [39]

To solve this problem it is necessary to apply the conservation equations of the moment for an inelastic impact or collision. In turn, it is necessary to apply the equations related to the conservation of potential energy and kinetic energy.

Mathematically this definition can be expressed as

m_1v_1+m_2v_2=(m_1+m_2)v_f

Where,

v_{1,2} = Initial velocity of each object

m_{1,2} =Mass of each object

v_f =Final velocity

Our values are given as

m_1 = 0.25kg\\m_2 = 0.5kg\\v_1 = 1.2m/s\\v_2 = 0m/s

Replacing we can find the value of the final velocity, that is

0.750v_f = 0.25*1.20+0.5*0

v_f = 0.4m/s

From the definition of the equations of simple harmonic motion the potential energy of compression and equilibrium must be subject to

KE_{compressed}+PE_{compressed} =KE_{equilibrium} +PE_{equilibrium}

Since there is no kinetic energy due to the zero speed in compression, nor potential energy at the time of equilibrium at the end, we will have to

0+\frac{1}{2}KA^2 = \frac{1}{2}(m_1+m_2)v_f^2+0

Re-arrange to find A

A = \sqrt{\frac{m_1+m_2}{k}v_f}

A = \sqrt{\frac{0.25+0.5}{10}(0.4)}

A = 0.11m

Finally, the period can be calculated through the relationship between the spring constant and the total mass, that is,

T = 2\pi \sqrt{\frac{m_1+m_2}{k}}

T = 2\pi \sqrt{\frac{0.5+0.25}{10}}

T = 1.7s

6 0
3 years ago
What question can a student BEST answer when comparing and contrasting the models?
Andru [333]

Answer:

A. how dose each model effect the temperature of a substance

Explanation:

3 0
3 years ago
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