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4 years ago

As an object increases in altitude, its mass: b. decreases c. remains the same

Physics

2 answers:

timama [110]4 years ago

8 0

Altitude, depth, or any other attributes of location, have no effect on mass.

mel-nik [20]4 years ago

4 0

No matter where you are, your mass stays the same. It's weight that changes. Also applies to any object.

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Please help me!!! ASAP 10 points for first to answer.

strojnjashka [21]

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7 0

3 years ago

Consider a helium balloon with volume 2.1 L.

Anna11 [10]

Answer:

The net force is 26.52 N

Explanation:

Given that,

Volume of balloon = 2.1 L

Density of air = 1.29 kg/m³

Mass = 1.3 g

Density of helium $\rho'= 0.18\times10^{-3}\ g/cm^3$

(a). We need to calculate the buoyant force on the balloon

Using formula of buoyant force

$F_{b}=\rho V g$

Put the value into the formula

$F_{b}=1.29\times\times2.1\times9.8$

$F_{b}=26.54\ N$

(b). We need to calculate the net force

Using formula of net force

$F_{net}=F_{b}-(V\times\rho'+m)\times g$

$F_{net}=26.54-(2.1\times10^{-3}\times0.18\times10^{-3}+0.0013)\times9.8$

$F_{net}=26.52\ N$

Hence, The net force is 26.52 N.

6 0

3 years ago

In a footrace between two runners, is it possible for the second-place finisher have a greater speed

tresset_1 [31]

Answer:

Explanation:

this may be wrong, but i would assume no because they have to cover the same distance therefore the faster runner would cross the finish line first.

3 0

3 years ago

A circuit has a 2Ω resistor in series with a 4Ω resistor. What is the total resistance of the circuit?

neonofarm [45]

Answer: 6Ω

Explanation:

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

R1 = 2Ω

R2 = 4Ω

Rtotal = ?

Rtotal = 2Ω + 4Ω

Rtotal = 6Ω

Thus, the total resistance of the circuit is 6Ω

4 0

3 years ago

Suppose that a stray neutron with an initial speed of 1.4 x 107 m/s is just barely captured by a nucleus with diameter d = 1.0 X

son4ous [18]

Answer:

$F=16.366N$

Explanation:

Given data

Initial velocity of neutron v₀=1.4×10⁷m/s

Diameter of nucleus d=1×10⁻¹⁴m

Mass of neutron m=1.67×10⁻²⁷kg

The acceleration of neutron is given from equation :

$v^{2}=v_{o}^{2}+2ad\\ where\\v=0\\So\\a=\frac{v^{2}-v_{o}^{2} }{2d}\\ a=\frac{-v_{o}^{2}}{2d}\\ a=\frac{-(1.4*10^{7}m/s )^{2}}{2(1.0*10^{-14} m)}\\a=-9.81*10^{27}m/s^{2}$

So its magnitude is a=9.81×10²⁷m/s²

To find magnitude of force we use Newtons second law of motion

$F=ma\\F=(1.67*10^{-27} kg)(9.81*10^{27}m/s^{2} )\\F=16.366N$

6 0

4 years ago