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dangina [55]
4 years ago
13

As an object increases in altitude, its mass: b. decreases c. remains the same

Physics
2 answers:
timama [110]4 years ago
8 0
Altitude, depth, or any other attributes of location, have no effect on mass.
mel-nik [20]4 years ago
4 0
No matter where you are, your mass stays the same. It's weight that changes. Also applies to any object.
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Briefly explain how a resonance tube works​
Lera25 [3.4K]

Answer:

As the tines of the tuning fork vibrate at their own natural frequency, they created sound waves that impinge upon the opening of the resonance tube. These impinging sound waves produced by the tuning fork force air inside of the resonance tube to vibrate at the same frequency.

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If you plan to exercise every day what is something you can do to make it more convenient so that you exercise more regularly?
jolli1 [7]

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Explanation:

4 0
3 years ago
Image.
AfilCa [17]
Answer : B - real

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2. The image will not be inverted

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3 years ago
Extra CreditA particle is directed along the axis of the instrument in the gure. Aparallel plate capacitor sets up an electric e
kvv77 [185]

This question is incomplete, the complete question is;

A particle is directed along the axis of the instrument in the figure below. A parallel plate capacitor sets up an electric field E, which is oriented perpendicular to a uniform magnetic field B. If the plates are separated by d = 2.0 mm and the value of the magnetic field is B = 0.60T.

Calculate the potential difference, between the capacitor plates, required to allow a particle with speed v = 5.0 × 10⁵ m/s to pass straight through without deflection.

<em>Hint </em>: ΔV = Ed <em> </em>

Answer:

the required potential difference, between the capacitor plates is 600 V

Explanation:

Given the data in the question;

B = 0.60 T

d = 2.0 mm = 0.002 m

v = 5.0 × 10⁵ m/s.

since particle pass straight through without deflection.

F_{net = 0

so, F_E = F_B

qE = qvB

divide both sides by q

E = vB

we substitute

E = (5.0 × 10⁵) × 0.6

E = 300000 N/C

given that; potential difference ΔV = Ed

we substitute

ΔV = 300000 × 0.002

ΔV = 600 V

Therefore, the required potential difference, between the capacitor plates is 600 V

5 0
3 years ago
Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×
ikadub [295]

Happy Holidays!

We can use the following equation to solve for the gravitational force:

\large\boxed{F_g = G\frac{m_1m_2}{r^2}}

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}

7 0
3 years ago
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