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Mademuasel [1]
1 year ago
9

Two trains leave a station at the same time. One train is heading south at a rate that is 1.5 times faster than the other train,

which is heading north. After 5 hours, the trains are 750 miles apart.
1) At what speed, in mph, are the two trains getting farther away from each other?
2) What is the speed, in mph, of the faster train?
3) Suppose the trains simultaneously leave stations that are 450 miles apart and travel toward each other. In how many hours will the trains meet?
Mathematics
2 answers:
shepuryov [24]1 year ago
7 0

Based on the data given, the speeds and time taken are as follows:

  1. The combined speed of the two trains is 150 mph
  2. The speed of faster train 150 x 3/5 = 90 mph
  3. The time taken by the trains to cover 450 miles = 3 hours

<h3>What is speed?</h3>

Speed is the ratio of distance covered and time taken.

  • Speed = distance/time

1)The distance covered by the two trains in 5 hours = 750 miles.

The trains move at a constant speed and their combined speed will be:

Combined speed = 750/5

Combined speed = 150 mph

2) The train heading south has a speed 1.5 times faster than the other train heading north.

Ratio of speeds = 3 : 2

Speed of faster train 150 x 3/5 = 90 mph

3) The combined speed of the trains = 150 mph

Distance to be covered = 450 miles

Time taken = 450/150

Time taken = 3 hours

In conclusion, the speed of the two trains are determined from the distance travelled and time taken.

Learn more about speed at: brainly.com/question/6504879

#SPJ1

amid [387]1 year ago
7 0

Answer:

1) 150 mph

2) 90 mph

3) 3 mph

Explanation:

1) The trains move at a constant speed, and after 5 hours they are 750 miles apart. 750/5=150

2) The faster train is 1.5 faster than the slower train, and we know their combined speed is 150 mph. 150/5=30, and 30x3=90.

3) We know that both trains combined travel 150 mph. 450/150=3.

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4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

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- Take √ for both sides

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∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

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