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Contact [7]
3 years ago
7

Find the equation of the straight line that passes through the point (1,1/2) and has slope 1/2. Enter the equation in the point-

slope form, y-...=...(x-...)
Mathematics
1 answer:
Nataliya [291]3 years ago
5 0
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 1}}\quad ,&{{ \frac{1}{2}}})\quad 
%   (c,d)

\end{array}
\\\quad \\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{1}{2}
\\ \quad \\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values}\\

\end{array}\\
\qquad \uparrow\\
\textit{point-slope form}
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Can someone give me some tips of how to study. I have already tried writing everything in my lesson but it doesn't seem to work
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A hotel offers a reward program based on the number of night stayed. The function f(x) represents the number of free nights earn
iris [78.8K]

Answer:

a. A customer earns 1 free night per 10 nights stayed.  

Step-by-step explanation:

The missing function is:

f(x) = x/10  

The missing options are:

<em> a. A customer earns 1 free night per 10 nights stayed.  </em>

<em> b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed. </em>

<em> c.A customer earns x – 10 free nights for every 10 nights stayed.  </em>

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which means 10 nights are equivalent to 1 free night.

7 0
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Answer:

{ \rm{y =  - 3x + 5}}

Gradient = -3

• Parallel lines have the same gradient, therefore gradient, m is -3

{ \rm{y = mx + c}}

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y intercept is -4

{ \boxed{ \boxed{ \mathfrak{answer : }}{ \rm{\:  \: y =  - 3x - 4}}}}

6 0
3 years ago
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