Question

I GIVE 62 POINTS!!!!!Please help me..I am struggling with this question and my assignment is overdue already..

Answer 1

A)

The formula for the distance in a given time, is x = vt - 0.5gt^2

where x is the distance

v is the initial velocity, given as 64 ft/s

g is the acceleration due to gravity which is equal to 32 ft/s^2

t is the time

Now you have:

x = 64t - 0.5(32)t^2

Simplify:

x = 64t -16t^2

Rearrange this so the exponent is first:

h(t) = -16t^2 +64t

B) See attached picture:

C) Maximum height was 64 feet. It reached maximum height in 2 seconds and total time in the air was 4 seconds.