The answer would be B because to have a function none of the x's can be the same, and we know that it's (x,y) so all of the first numbers are x's In the first answer choice the x's would be 0,1,3,5,&5 but the 5 is repeated so we toss that answer choice In answer choice B, the x's are 3,4,&5, so that's a maybe In C, the x's are 1,5,1,&5 so we know that's not correct because the 5's and the 1's are both repeated Last but not least, in D, the x's are 5,7,&5, the 5's are repeated so that leaves us with our answer of B. {(0,1), (1,2), (3,4), (5,6), (5,7)}
To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:
32a^3 + 12a^2
a^2 (32a + 12)
Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:
a^2 (32a + 12)
4a^2 (8a + 3)
So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).