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marusya05 [52]
3 years ago
12

Subtract (3x - 7x^2 + 2) - (4x^2 - 5 + 6x)

Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

-3x-11x²+7

Step-by-step explanation:

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Suppose the position of an object moving in a straight line is given by s (t )equals 4 t2+ 5 t+ 5. Find the instantaneous veloci
VLD [36.1K]

Answer:

v(t) = 8t +5

And that represent the instantaneous velocity at a given time t.

And then we just need to replace t =2 in order to find the instantaneous velocity and we got:

v(t=2) = 8*2 + 5 = 16+5 = 21

Step-by-step explanation:

For this case we have the position function s(t) given by:

s(t) = 4t^2 + 5t+5

And we can calculate the instanteneous velocity with the first derivate respect to the time, like this:

v(t) = s'(t)= \frac{ds}{dt}

And if we take the derivate we got:

v(t) = 8t +5

And that represent the instantaneous velocity at a given time t.

And then we just need to replace t =2 in order to find the instantaneous velocity and we got:

v(t=2) = 8*2 + 5 = 16+5 = 21

4 0
3 years ago
How to solve it this problem
nikdorinn [45]
The question asks us to find m∠ABC. We know that ray BD is a bisector of ∠ABC. So, all we need to do now is equate the expressions of ∠ABD and ∠DBC to the expression of ∠ABC. Here is what we get from this:
(9x-7)+(3x+17) = 16x-2
Now, just solve for x. When doing so, we get the answer x = 3. Since we have the value for x, all we need to do is plug in that value to the expression for ∠ABC, which would result in 46. This means that the answer to your query is ∠ABC = 46°. Hope this helps and have a phenomenal day!
5 0
4 years ago
Solve the equation below. -3 1/4x + 25=2 1/4x - 13 1/2
frozen [14]

Answer:

x=7

Explanation:

-3 1/4x+25= 2 1/4x-13 1/2

25=5 1/2x-13 1/2

38 1/2=5 1/2x

7=x

5 0
3 years ago
The x-intercepts and vertex
Veronika [31]

( - 6, 0).(2, 0 ) , vertex = ( - 2, - 16)

to find the x-intercepts set f(x) = 0

x² + 4x - 12 = 0

(x + 6)(x - 2) = 0 ( equate each factor to zero and solve for x )

x + 6 = 0 ⇒ x = - 6

x - 2 = 0 ⇒ x = 2

x- intercepts are ( - 6, 0),(2, 0)

given the quadratic in standard form : y = ax² + bx + c

the x-coordinate of the vertex = - \frac{b}{2a}

here a = 1 , b = 4 and c = - 12

x- coordinate of vertex = - \frac{4}{2} = - 2

substitute this value into the equation for y-coordinate

x = - 2 → y = 4 - 8 - 12 = - 16

vertex = ( - 2, - 16)


5 0
4 years ago
Find the sum.<br> 14,389 + 4,309
pochemuha

Answer:

18698

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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