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2 years ago

14

How do you find the leg of a triangle?

1 answer:

Law Incorporation [45]2 years ago

4 0

If it is right triangle use pythagorean

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Please help me with this homework

yulyashka [42]

I disagree. The first one is false. No exponent rules apply if the bases AND the exponents are different.

The second one is true. Bases are the sane so you add exponents. You get 3 to the -5 power. Written with positive exponents it’s 1/3 to the 5.

7 0

2 years ago

Please help |3r -6| =21

julsineya [31]

3r-6=-21

3r-6+6=-21+6 (Add 6 to both sides...)

3r=-15

r=-5

3r-6=21

3r-6+6=21+6 (Add 6 to both sides...)

3r=27

r=9

r=-5 or r=9

8 0

2 years ago

Read 2 more answers

I need the answer pls reply

just olya [345]

Answer:

2 is the answer I did this once in class

4 0

2 years ago

Which expression is equivalent to *picture attached*

Sedbober [7]

Answer:

$\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

Step-by-step explanation:

Given expression : $\sum_{n=3}^{20}(n(n+1))$

Solving further :

$\Rightarrow \sum_{n=3}^{20}(n^2+n)$

$\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, $\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, The given expression is equivalent to Option A

So, Option A is the answer

7 0

3 years ago

Verify it as fast as you can

melamori03 [73]

Answer:

(a+6)²

by identity (a+b)²=a²+2ab+b²

(a+6)²= a²+ 2×a×6 + 6²

= a²+ 12a + 36

(2a)²+5a = 4a²+5a

5 0

2 years ago