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Darya [45]
3 years ago
10

Wrench sets designed for SI bolts often include wrenches at 1 mm increments while wrench sets designed for imperial bolts often

include wrenches at 1/16" increments. With only a metric wrench set on hand, which metric wrench would best fit a 5/8" bolt?
Mathematics
1 answer:
juin [17]3 years ago
3 0
So 5/8 inches to milimeters
we know that 1 in=2.54 cm so
5/8 in times 2.54= 1.5875 cm
1 cm=10 mm
1.5875 cm times 10=15.875mm aprox 16 mm, but best to go smaller since it won't fit if bigger

answer: 16mm (my recomendation would be 15mm)
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What is two thirds equal to
Luden [163]

Answer:

2/3 = 0.6666666666666667 or just 67%.

Step-by-step explanation:

5 0
3 years ago
On a piece of paper, use a protractor and a ruler to construct △ABC with AB=4 in., AC=4 in., and m∠A=60°.
ollegr [7]

Answer:

BC 4 in

Step-by-step explanation:

The steps for construction;

  • Using a ruler draw line AB 4 inches  and label the end points A and B
  • At point A , using a protractor, measure angle 60° and mark with point. Draw a line from A passing through this point extending to a length of 4 inches
  • Mark that point C.
  • Using the ruler, join point C and B and measure BC.

From calculation, length BC can be found by the formula;

BC=\sqrt{a^2+b^2-2*a*b*cosA}------where a=b=4 in , cos A = cos 60°

BC=\sqrt{4^2+4^2-2*4*4*cos60}

BC = 4 in

6 0
2 years ago
Read 2 more answers
FIRST CORRECT ANSWER GETS BRAINLIEST
uranmaximum [27]
<span>L = </span>α<span> * R where L is the length of the arc of the circle, R is the radius of the circle, and </span>α<span> is the central angle expressed in radians, so

</span>R =  \cfrac{L}{ \alpha }= \cfrac{10 \pi }{ \frac{5 \pi }{6} }  = \cfrac{10 \pi *6}{5 \pi }=2*6=12 \ units<span>
</span>
6 0
3 years ago
The number of cubic inches in the volume of a 6-inch high cylindrical can equals the number of square inches in the area of the
Svetradugi [14.3K]

Answer:

In inches, the radius of the can is <u>2</u>.

Step-by-step explanation:

Given:

The number of cubic inches in the volume of a 6-inch high cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.

Now, to find the radius of the can in inches.

Let the radius of can be r.

Height of can = 6\ inches.

<em>As given, the number of cubic inches of the volume of the cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.</em>

<em><u>So, </u></em>

<em><u>Volume of can = lateral surface area of can.</u></em>

Now, we put formula of volume and lateral surface area of cylinder:

\pi r^2h=2\pi rh

\pi \times r\times r\times 6=2\times \pi \times r\times 6

<em>Dividing both sides by </em>\pi \times r<em> we get:</em>

<em />r\times 6=2\times 6<em />

<em />6r=12<em />

<em>Dividing both sides by 6 we get:</em>

r=2.

Therefore, in inches, the radius of the can is <u>2</u>.

8 0
3 years ago
Estimate 73,404 +27,865
wlad13 [49]
An estimate here would be 73,500+ 28,000= 101,500 but the actual answer would be 101,269
8 0
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