Answer: i. Cost of adult ticket = $ 30
ii. Cost of child ticket = $20
Step-by-step explanation:
Define variables:
Let x= cost of 1 adult tickets , y= cost of 1 child tickets.
Form linear equations:
5x+3y = 210 (i)
2x+5y= 160 (ii)
Multiply (i) by 2 and (ii) by 5
10x +6y = 420 (iii)
10x+25y = 800 (iv)
Eliminate (iii) from (iv)
19y = 380
⇒ y= 20
Put this in (i)
Hence, Cost of adult ticket = $ 30 and Cost of child ticket = $20
Answer:
No solution is possible from the information given.
The area of the lawn is unknown.
Step-by-step explanation:
№1. Given: r=8 ft, π≈3.14
C=2×π×r=2×3.14×8=50.24=50.2 ft
A=π×r²=3.14×64=200.96=201 ft²
Answer: 50.2 ft; 201 ft²
№2. Given: D=11 cm, π≈3.14
d=2r or r=2/d, so if d is 11 cm, then r is 11÷2=5.5 cm
C=2×π×r=πD=3.14×11=34.54=34.5 cm
A=π×r²=3.14×(5.5)²=94.985=95 cm²
Answer: 34.5 cm; 95 cm²
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
