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2 years ago

To which group does copper belong?

Chemistry

1 answer:

Lostsunrise [7]2 years ago

3 0

Answer:

d. Transition metal

Explanation:

A transition metal is an element which has an atom or forms an ion with a partially-filled d-subshell.

As we can see from the electronic configuration of Copper 2+ ion, Cu²⁺:

$_{27}Cu^{2+} = 1s^2\space\ 2s^2 \space\ 2p^6 \space\ 3s^2 \space\ 3p^6 \space\ 3d^9$ ,

copper forms an ion with an incomplete d-subshell that contains 9 electrons; therefore copper is a transition metal.

• Option a. is wrong because copper is not a metalloid. Metalloids have characteristics of both metals and non-metals; copper only has metallic properties.

• Option b. is wrong because 'alkaline earth metals' are the elements in Group 2 of the periodic table; copper is in Group 11.

• Option c. is wrong because 'alkali metals' are in Group 1 of the periodic table.

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Determine the elements with these electron configurations

lakkis [162]

Use a periodic table. Count the exponent for your atomic number. So, 1s2 2s2 2p5= Fluorine
1s2 2s2 2p6 3s2 3p5= Chlorine
1s2 2s2 2p6 3s2 3p6 4s2 3d6= Iron

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3 years ago

What does towels represents on earth?

Kamila [148]

The build up sediment of the sea bottom

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3 years ago

An atom has a mass number of 24 and 13 neutrons. what is the atomic number of this atom?

Elodia [21]

do ityou times 24×13=312.

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4 years ago

Which reactions are oxidation-reduction reactions? Check all that apply

tia_tia [17]

2 Na + Cl₂ → 2 NaCl

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag

CH₄ + 2 O₂ → CO₂ + 2 H₂O

are oxidation-reduction reactions

Explanation:

In the oxidation-reduction reaction there is a component which accept electrons and it is reduced and another component which donates electrons and it is oxidized.

Now in the case of the reaction of copper (Cu) with silver nitrate (AgNO₃):

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag

Cu⁰ with a oxidation number 0 donates 2 electrons⁻ and is transformed in Cu⁺² with the oxidation number 2+.

Ag⁺ with a oxidation number 1+ accepts 1 electron⁻ and is transformed in Ag with the oxidation number 0.

In the case of CH₄ + 2 O₂ → CO₂ + 2 H₂O reaction we have:

C⁴⁻ with a oxidation number +4 donates 8 electrons⁻ and is transformed in C⁴⁺ with the oxidation number 4+.

O⁰ with a oxidation number 0 accepts 2 electrons⁻ and is transformed in O²⁻ with the oxidation number 2-.

And in the case of 2 Na + Cl₂ → 2 NaCl reaction we have:

Na⁰ with a oxidation number 0 donates 1 electron⁻ and is transformed in Na⁺ with the oxidation number 1+.

Cl⁰ with a oxidation number 0 accepts 1 electron⁻ and is transformed in Clwith the oxidation number 1-.

Learn more about:

oxidation-reduction reactions

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#learnwithBrainly

4 0

3 years ago

Calculate the volume of H2(g) at 273 K and 2.00 atm that will be formed when 275 mL of 0.725 M HCl solution reacts with excess M

Ksenya-84 [330]

Answer:

$V=1.11L$

Explanation:

Hello,

In this case, the chemical reaction is:

$2HCl+Mg\rightarrow MgCl_2+H_2$

Thus, the reacting moles of hydrochloric acid are computed with the volume of the given solution:

$n_{HCl}=0.725\frac{mol}{L} *0.275L=0.199molHCl$

Hence, we perform the proportional factors having the 2:1 molar relationship between hydrochloric acid and hydrogen to find the yielded moles of hydrogen:

$n_{H_2}=0.199molHCl*\frac{1molH_2}{2molHCl} =0.0995molH_2$

Finally, by using the ideal gas equation we obtain the volume for the specified conditions as shown below:

$V=\frac{nRT}{P} =\frac{0.0995molH_2*0.082\frac{atm*L}{mol*K}*273K}{2.00atm} \\\\V=1.11L$

Best regards.

4 0

3 years ago

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