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VashaNatasha [74]
2 years ago
11

If we have five decisions to make and four choices for each decision, how can we represent the number of potential outcomes?

Mathematics
1 answer:
Kazeer [188]2 years ago
4 0

Using the Fundamental Counting Theorem, the number of potential outcomes is given by: 4^5

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

There are five decisions, each with four options, hence:

n_1 = n_2 = n_3 = n_4 = n_5 = 4

The number of options is:

N = 4 \times 4 \times 4 \times 4 \times 4 = 4^5.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

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3 years ago
State the rule obeyed by the variables in each relation diagram below
labwork [276]

Answer:

y = 2x + 1

Step-by-step explanation:

You can see a pattern in the group of x's that the numbers go up by 1 Also in the y-set that the numbers go up by 2. So this pattern is linear, that means the "rule" you are looking for does not have exponents or square roots or any very complicated stuff. You can use a guess and check method. Say to yourself how can I get a 7 out, when I put a 3 in? "times by2 and plus 1" works.

3 times 2, and plus1

gives you 7.

Test it on the other numbers.

-1 times2, and plus1

2(-1)+1 = -1

2(0)+1 = 1

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2(2)+1 = 5

It works for all the numbers.

You can calculate it also, using any two pairs of (x,y) from the data set. Put y-y on top of a fraction and x-x on the bottom. You will get the slope and that is the 2 in the "rule"

(3,7) and (2,5) for example. 7-5 so put 2 on top and 3-2 so put 1 on the bottom. 2/1 is just 2. From the point (0,1) we know the y-intercept is 1. This also gives the equation y=2x+1.

If you are just starting to learn this, probably just guess and check a rule. The rule has to work for all the points.

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2 years ago
Factor the following quadratic equation; <br><img src="https://tex.z-dn.net/?f=12%20%7Bx%7D%5E%7B2%7D%20%20%2B%2022x%20-%2014" i
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Step-by-step explanation:

You can see it a little easier if you take out a common factor of 2

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Let 6 factor into 2 and 3 and the 7 into 7 and 1

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Now remove the brackets.

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2(6x^2 + 19x - 7)

So we'll try it again

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2(6x^2 + 14x - 3x - 7)    Looks like we have it.

2(6x^2 + 11x - 7)

So the right factors are

2(3x + 7)(2x - 1)

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