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VashaNatasha [74]
2 years ago
11

If we have five decisions to make and four choices for each decision, how can we represent the number of potential outcomes?

Mathematics
1 answer:
Kazeer [188]2 years ago
4 0

Using the Fundamental Counting Theorem, the number of potential outcomes is given by: 4^5

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

There are five decisions, each with four options, hence:

n_1 = n_2 = n_3 = n_4 = n_5 = 4

The number of options is:

N = 4 \times 4 \times 4 \times 4 \times 4 = 4^5.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

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