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mr_godi [17]
3 years ago
7

The solids are similar. Find the surface area S of the red solid.

Mathematics
1 answer:
Brut [27]3 years ago
5 0
The refresh is a little hard was
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5y+3+4x identify parts in an algebraic expression
Sphinxa [80]

Answer:

y and x are variables, the 5 in 5y is a coefficient so is the 4 in 4x, the 3 is called a constant

Step-by-step explanation:

7 0
3 years ago
AaaHHHHH I NEED MORE HELP!!
nalin [4]

Answer:

90 -63=27 so the answer is 27 because complementary angles add to 90

4 0
2 years ago
See attachment for the whole question.
KengaRu [80]

Using probability concepts, it is found that:

a) \frac{4}{13} probability of drawing a card below a 6.

b) \frac{4}{9} odds of drawing a card below a 6.

c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

------------------------------

  • A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

Item a:

  • In a standard deck, there are 52 cards.
  • There are 4 types of cards, each numbered 1 to 13. Thus, 4 \times 5 = 20 are less than 6.

Then:

p = \frac{20}{52} = \frac{4}{13}

\frac{4}{13} probability of drawing a card below a 6.

Item b:

  • Converting from probability to odd, it is:

\frac{4}{13 - 4} = \frac{4}{9}

\frac{4}{9} odds of drawing a card below a 6.

Item c:

  • The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
  • Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

A similar problem is given at brainly.com/question/24233657

7 0
3 years ago
At a fixed operating setting, the pressure in a line downstream of a reciprocating compressor has a mean value of 950 kPa with a
prisoha [69]

Answer:

4.75% probability that the line pressure will exceed 1000 kPa during any measurement

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 950, \sigma = 30

What is the probability that the line pressure will exceed 1000 kPa during any measurement

This is 1 subtracted by the pvalue of Z when X = 1000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1000 - 950}{30}

Z = 1.67

Z = 1.67 has a pvalue of 0.9525

1 - 0.9525 = 0.0475

4.75% probability that the line pressure will exceed 1000 kPa during any measurement

7 0
3 years ago
Christy subtracted to find her jogging rate for each time period and said that her rate
bulgar [2K]

Answer:

No, Christy subtracted to find her jogging rate. Not added.

Step-by-step explanation:

The common diffrnece is +4 so she whould have to add. I hope this helps

5 0
2 years ago
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