Does 10p/2q = 5p/q I don't think so but it doesn't seem right.
2 answers:
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Answer:
0.29
Missing Problem Statement:
The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random
sample of 870 teenagers aged 13–18 in a large urban city.
Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
Frequency 170 82 220 153 92 58 40 15 12 18 10
Step by Step Explanation:
First we need to find the estimated probability distribution for teens spending time texting.
For that we need,
Total sample size = 870 teenagers (as given in the problem statement)
Estimated probability distribution (Frequency*) =
Example:
Estimated probability distribution that teens spend 0 hours=
Similarly,
Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
Frequency*0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01
We need, estimated probability distribution that teens spend less than an hour per day, so from the above result:
<u>Estimated probability distribution of teens spending 0 hour per day =0.2 </u>
<u>Estimated probability distribution of teens spending 0.5 hour per day = 0.09 </u>
Estimated probability distribution of teens spending less than an hour per day= 0.2+0.09=0.29