All categories

2 years ago

The following three shapes are based only on squares, semicircles, and quarter circles.

Mathematics

1 answer:

grin007 [14]2 years ago

4 0

The perimeter of the shaded part is: 25.1 cm.

The area of the shaded part is: 36.6 cm².

<h3>How to Find the Perimeter and Area of the Shaded Part?</h3>

Area = Area of square - 2(area of square - area of quarter circle) = s² - 2(s² - 1/4πr²).

Parameters given are:

s = 8 cm
r = 8 cm

Plug in the values into the equation

Area = 8² - 2(8² - 1/4π(8²)).

Area = 64 - 2(64 - 50.3)

Area = 36.6 cm²

Perimeter = 2(perimeter of quarter circle) = 2(1/4(2πr)) = 2(1/4(2π8)) = 25.1 cm

Learn more about perimeter and area on:

brainly.com/question/443376

#SPJ1

You might be interested in

marksman takes eight shots at a target he normally list the target 70% of the time what is the probability that he luits the tar

xxTIMURxx [149]

70% equals 0.7 *8/6= 34

5 0

3 years ago

Solve by using proper methods. Show your work.

NeX [460]

Answer:

$70,201.38

Step-by-step explanation:

To determine the principal amount, we can use the formula:

$P=\dfrac{A}{(1+\frac{r}{n})^{nt}}$

A = $200,000

r = 7% or 0.07

t = 15 years

n = 12

Now let's substitute our values.

$P=\dfrac{200,000}{(1+\frac{0.07}{12})^{12(15)}}$

$P=\dfrac{200,000}{(1.00583333333)^{12(15)}}$

$P=70,201.38$

So the principal needed to get 200,000 in 15 years is $70,201.38.

7 0

3 years ago

Nathan wants to buy a car that costs $25,920 he has $3,000 as a down payment and his payments will be $450 for 6 years through r

sesenic [268]

he payed 3,000 in hand payment then gave checks per...mnth for 6 years to equal the needed amount

3 0

3 years ago

A pilot can travel for 140 miles with the wind in the same amount of time as 360 miles against the wind. Find the speed of the w

quester [9]

Answer:

-88 mph

Step-by-step explanation:

We can use the relation ...

time = distance/speed

to compare the times in the two directions.

$\dfrac{140}{200+w}=\dfrac{360}{200-w}\\\\140(200-w)=360(200+w)\\\\200(140-360)=w(360+140)\\\\w=\dfrac{200(-220)}{500}=-88 \quad\text{miles per hour}$

The wind speed is -88 miles per hour.

_____

The problem statement tells us the travel is slower <em>with</em> the wind than <em>against</em> the wind. Hence "with the wind" must be subtracting from the net speed. That is, the wind speed is negative.

4 0

3 years ago

HELP!!!! PLEASE!!!!!!!

Sindrei [870]

Answer:

I cant really see the questions

Step-by-step explanation:

6 0

3 years ago