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hodyreva [135]
3 years ago
9

Joe went to the hobby shop and bought 2 model sports cars at $8.95 each and some paints. If he spent a total of $23.65, what was

the cost of the paints
Mathematics
1 answer:
Gala2k [10]3 years ago
8 0
Since he bought 2 model cars for $8.95 each, he bought both for $17.90. Now, subtract this from the total cost to get the cost of paint. $23.65-$17.90=$5.75. So, the total costs of paints are $5.75. Hope this helped!
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Siska wants to buy 5 packs of chocolate , which will cost $ 3,25 each. If ahe pays with 2 sheets of $10 , how much change will s
GarryVolchara [31]

$3.75

Step-by-step explanation:

times 3.25 by 5 which is 16.25 then do 20 - 16.25

3 0
3 years ago
A shoe store uses a markup rate 40% when determining the retail price of its items. If the store pays $42.25 for a pair of shoes
KatRina [158]
$59.15

42.25 x .4 = 16.90
42.25 + 16.90 = 59.15
3 0
3 years ago
If the answer and the explanation are right I'll given brainliest.
Anna007 [38]

Answer:

>

Step-by-step explanation:

d>1/3

d is greater than 1/3

not much to it

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3 years ago
Read 2 more answers
5.) Mother went to the supermarket. She bought 1.8 kg of chicken at Php120.50 a kilo
lutik1710 [3]

Answer:

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4 years ago
A piece of wire 40 cm long is to be cut into two pieces. One piece will be bent to form a circle and; the other will be bent to
Brums [2.3K]
<h3>The perimeter of circle  = 17.6 cm</h3><h3>Perimeter of square  = 22.4 cm</h3>

Step-by-step explanation:

The total length of the wire  = 40 cm

Let us assume the circumference of the circle  = k cm

So, the circumference of the square  = ( 40 - k) cm

Now,as circumference of circle = 2πR

⇒2πR = k cm    or, R  = (\frac{k}{2\pi})

Area  of the  circle = πR²  

or, A  = \pi (\frac{k}{2\pi} )^2  

 = \pi \times (\frac{k^2}{(2\pi)^2} )  = \frac{k^2}{4 \pi} \\\implies A =  \frac{k^2}{4 \pi}   ....... (1)

Similarly , perimeter of square  = 4 x Side

⇒ 4 x Side  =  ( 40 - k) cm    ⇒ S = (\frac{40 - k}{4} )

Area  of the  square = (Side)²    = (\frac{40 - k}{4} ) ^2

 Solving, we get:  A = \frac{1600 + k^2 - 80 k}{16}   ....... (1)

So, combining (1) and (2), total area A is

A = (\frac{k^2}{4 \pi} ) + \frac{k^2 + 1600 - 80 k }{16}

or, we get: A  = 0.07962 k²  + 0.0625 k² + 100 - 5 k

A  =  0.1422 k² - 5 k + 100

For axis of symmetry :  k = (\frac{-b}{2a} ) = (-\frac{-5}{2(0.1420})  = 17.6

⇒ k = 17.6 inches

So, the perimeter of circle  = 17.6 cm

Perimeter of square  = (40 - 17.6 )  = 22.4 cm

3 0
3 years ago
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