The line ax − by + 3 = 0 is parallel to the line 3x + 2y − 4 = 0 and passes through the point (1, −2). Find a and b.
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x + 6y = 12
You want the y-value to be on one side of the equation, so you have to subtract the x-value from both sides.
6y = -x + 12
Next, you divide both sides by 6, so that the y-value will be by itself.
y = - + 2
We know that the slope or the 'm' value is located before the x-value based on y = mx +b, therefore the slope is -