f(x)=2x^3+2x^2-4x
The zeros of polynomial functions
2x^3 + 2x^2 - 4x = 0
2x(x^2 + x - 2) = 0
2x(x - 1)(x + 2) = 0
2x = 0; x = 0
x - 1 = 0; x = 1
x + 2 = 0; x = -2
Answer
x = -2 , 0 , 1
Answer = 5.656854249
Step by step:
This equation is just a simple Pythagorean theorem ( if you were not aware, it’s a2 + b2 = c2. To get c is to find the square root of c)
Answer:
π/90 or 0.0035 units
Step-by-step explanation:
equation: <em>length of the arc = ∠of the angle/360 * circumference</em>
Substitute: <em>S = 0.4/360 * 10π</em> --> C = 2πr
Simplify: S = 1/900 * 10π
Simplify: S = π/90 ≈ 0.003489 units
<u> 4 x² = 64</u>
Divide each side by 4 : x² = 16
Take the square root
of each side: x = √16
x = <em>+ 4</em>
and
x = <em>- 4</em> .
