Lets see the answer to this question the fraction of the entire load of dirt in each mound is b.1/2 this is how i got my answer you multiply 3*1/6=1/2 so the fraction of the entire load of dirt that was in each mound is 1/2
Answer:
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
Step-by-step explanation: See Annex
Green Theorem establishes:
∫C ( Mdx + Ndy ) = ∫∫R ( δN/dx - δM/dy ) dA
Then
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy
Here
M = 2x + cosy² δM/dy = 1
N = y + e√x δN/dx = 2
δN/dx - δM/dy = 2 - 1 = 1
∫∫(R) dxdy ∫∫ dxdy
Now integration limits ( see Annex)
dy is from x = y² then y = √x to y = x² and for dx
dx is from 0 to 1 then
∫ dy = y | √x ; x² ∫dy = x² - √x
And
∫₀¹ ( x² - √x ) dx = x³/3 - 2/3 √x |₀¹ = 1/3 - 0
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
Really, we don't need to use that much math--we can use logic instead. Since the two congruent sides must be longer than 30in, the total has to be greater than 60in (the longest side plus the congruent sides.) So for our answer, we want the smallest total that is above sixty, which in this case is 72.44in.
Hope I helped, and let me know if you have any questions :) I can explain the real math if you want, it was just unnecessary here.
There is an inverse corollation between the values of A and B. Specifically, a 3 unit change increase in A results in a 4 unit decrease in B
a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
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