(I know there isnt any real problem here to solve, but heres a tip on how to solve greatest to least with decimal problems)
1. Just because a number looks big, doesn't mean it is big
Example: 1.00000000000001 < 1.1
just look at the numbers ^ and dont just hastily read it over assuming that 1.1 is smaller because it "has less digits"
2. Negative numbers are... opposite. and they are less than positive numbers
-3.4 > -4.1
Why is this? Well, if you look on a line, with the point 0 in the middle, you can see that -3.4 is not as far away from 0 as -4.1 is. So the idea is to apply opposite logic for negative numbers
I hope these tips helped!! :D
10/8 in simplest form:
First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.
Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8
We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.
Second, divide the numerator and the denominator by the GCF (2).

Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get:

Answer in fraction form:

Answer in decimal form:

Answer in mixed number form:
The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.
A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.
The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.
In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.
Hence we can generally infer that the given statement is false.
To learn more about confidence intervals visit:
brainly.com/question/24131141
#SPJ4
Answer:
K of Kelvin
Step-by-step explanation:
Set up a x/100 = (14-48)/48 = -34/48 Multiply the cross 48x = -3400 x = 70.8333 so around -70.83% change