Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>
where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.
P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)
… = P(<em>Z</em> < 0.24)
… ≈ 0.5948
Answer:
270.00 divided by 32 = about $8.44
Answer:
a; she will have $8812
b: It will be enough for her trip
Step-by-step explanation:
In this question, we are tasked with calculating how much a certain value in a savings account that is earning an interest that is compounded annually will be worth.
To calculate this, we use the compound interest formula;
A = P(
Where A is the amount after that number of years which of course we want to calculate
P is the principal amount which is the amount we are investing which is $6439 according to the question
r is the interest rate which is 4% = 4/100 = 0.04
t is the time which is 8 years
n is 1 which is the number of times interest will be compounded annually
We plug these values as follows;
A = 6439(1 + 0.04/1)^8
A = 6439(1.04)^8
A = $8,812.22
This amount is greater then the needed $8,500 for the trip and of course it will be enough
Let the amount invested at 4% be = x
Let the amount invested at 3% be = y
Given is:
or
.... (1)
As, total income for the two investments is $194, so equation is:
....(2)
Putting value of x from (1) in (2)




And x=5200-y

Hence, money invested at 4% is $3800 and money invested at 3% is $1400
Answer:
L = w+2
L+w = 60
W+2+w = 60
2w+2 = 60
W+1 = 30
W = 29
L = 31