Question

How to find minimum and maximum of this equation.

Answer 1

Using it's vertex, the maximum value of the quadratic function is -3.19.

What is the vertex of a quadratic equation?

A quadratic equation is modeled by:

$y = ax^2 + bx + c$

The vertex is given by:

$(x_v, y_v)$

In which:

• $x_v = -\frac{b}{2a}$

• $y_v = -\frac{b^2 - 4ac}{4a}$

Considering the coefficient a, we have that:

• If a < 0, the vertex is a maximum point.

• If a > 0, the vertex is a minimum point.

In this problem, the equation is:

y + 4 = -x² + 1.8x

In standard format:

y = -x² + 1.8x - 4.

The coefficients are a = -1 < 0, b = 1.8, c = -4, hence the maximum value is:

$y_v = -\frac{1.8^2 - 4(-1)(-4)}{4(-1)} = -3.19$

More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

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