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Serjik [45]
2 years ago
14

How to find minimum and maximum of this equation.

Mathematics
1 answer:
Westkost [7]2 years ago
3 0

Using it's vertex, the maximum value of the quadratic function is -3.19.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the equation is:

y + 4 = -x² + 1.8x

In standard format:

y = -x² + 1.8x - 4.

The coefficients are a = -1 < 0, b = 1.8, c = -4, hence the maximum value is:

y_v = -\frac{1.8^2 - 4(-1)(-4)}{4(-1)} = -3.19

More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

#SPJ1

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Answer:

Option (C)

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