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valentina_108 [34]
2 years ago
5

A company rents moving trucks for $45 plus $0.75 per mile. write an equation that relates the cost C and the miles driven, x. Ca

lculate the cost of
renting a truck for one day, and driving it 110 miles.
Mathematics
2 answers:
Flura [38]2 years ago
8 0
Took test thanks good luck
polet [3.4K]2 years ago
6 0

The equation we would use here would be 45 + 0.75x = C

This is because we have a flat fee of $45 and you are being charged $0.75 per mile, so it depends on how many miles were driven.

To find out how much it would cost if it were to drive 110 miles, we simply put 110 in place of x;

45 + 0.75(110) = C

And now we solve!

45 + 82.50 = C

$127.50

Hope this helps!

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In 3 years, Dianna will be 4 times as old as she was 33 years ago. How old is Dianna now?
Sergeu [11.5K]

Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.

<h3>How old is Dianna now?</h3>

Given that, in 3 years, Dianna will be 4 times as old as she was 33 years ago.

Let x represent the age of Dianna presently.

Dianna's age in 3 years time will be: x + 3

Dianna's age 33 years ago is: x - 33

Since in 3 years, she will be 4 times as old as she was 33 years ago.

x + 3 = 4( x - 33 )

We solve for x

x + 3 = 4x - 132

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135 = 3x

x = 135/3

x = 45

Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.

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4 0
2 years ago
Susie starts her hike at 255 feet below sea level when she reaches the end of the hike she is still below sea level at -178 feet
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98 was the change in elevation

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3 years ago
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
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Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

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Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
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