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pishuonlain [190]
2 years ago
12

HELP ME PLEASE I WILL GIVE POINTS THANK YOU SO MUCH

Mathematics
1 answer:
sineoko [7]2 years ago
8 0

The angle of X is 108°

Given,

XW ≅ YZ

∠Z = 72°

then ∠X = ?

Properties of trapezoid are:

  • The base sides are the only pair of sides that are parallel. 
  • Other than the base, the remaining sides are all non-parallel and equal in length. 
  • The length of the diagonals is constant. 
  • the same for the base angles. 

We know that from the figure that ∠Z = ∠V & ∠W = ∠U

∵ Isosceles trapezoid rule

And sum of all the angles in a trapezoid = 360°

Now, 2 × 72 = 144

∴ 360 ₋ 144 = 216°

Now sum of other two angles = 216°

                              one angle = 216/2

                                               = 108°

Therefore the angle of ∠X is 108°

Learn more about "Quadrilateral" here-

brainly.com/question/16691874

#SPJ10

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Answer:

Lateral surface area of the cylinder =251.2 cm^2

Step-by-step explanation:

  Lateral surface area of he cylinder = 2*\pi*r*h  i.e area of side surface.

Height(h) = 5 cm

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radius(r)= 16/2= 8 cm

Lateral surface area of the cylinder = 2*\pi *8*5                        

                                                                         \pi =\frac{22}{7}=3.14

               L.S.A=  2*3.14*8*5

              L.S.A=  251.2 cm^2

The lateral surface area of the cylinder with radius 8 cm and height 5 cm is 251.2 cm^2

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Linear expression

Step-by-step explanation:

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Answer:

x-2y-4z=8\\5x-4y+7z=5\\-7x+5y+2z=-3

Step-by-step explanation:

Given the matrix equation below:

\left(\begin{array}{ccc}1&-2&-4\\5&-4&7\\-7&5&2\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}8\\5\\-3\end{array}\right)

We are required to write the matrix equation as a system of linear equations without matrices.

\left(\begin{array}{ccc}1&-2&-4\\&&\\&&\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}8\\&\\&\end{array}\right)$is equivalent to: x-2y-4z=8

\left(\begin{array}{ccc}\\5&-4&7\\&&\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}&\\5\\&\end{array}\right)$ is equivalent to: 5x-4y+7z=5

\left(\begin{array}{ccc}&\\&\\-7&5&2\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}&\\&\\-3\end{array}\right)$ is equivalent to: -7x+5y+2z=-3

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x-2y-4z=8\\5x-4y+7z=5\\-7x+5y+2z=-3

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G = 0.75s

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