Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
You would do $5.67 divided by three. one pen is $1.89
Step-by-step explanation:
all angles of a triangle sum to 180
180 = 15x + 24x +21x
180=60x
solve for x
then substitute that for 24(x) to get the angle
Answer:
J < -7
Explantion:
Rewrite so J is on the left side
-20j > 140
Divide each term by -20 and simplify
j < -7
Well, that means that it is 3 more than a common multipule of 8,10,12, and 30
find the lcm
8=2*2*2
10=2*5
12=2*2*3
30=2*3*5
lcm=2*2*2*3*5=120
times it by 2 to get it between 200 and 500
240
add 3
243 is da number
