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iVinArrow [24]
2 years ago
13

Find the area of the circle with a circumference of

Mathematics
1 answer:
Anton [14]2 years ago
8 0

Answer:

706.50 mm^2

Step-by-step explanation:

The formula to find the circumference is 2πr (r : radius)

if the circumference is 30π the the radius is = 15

to find the area we use the following formula :

π*r^2

r = 15 and π is given as 3.14

(3.14)*15^2 = 706.50 mm^2

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Twice a number is 12 more than 5 times the number.
stira [4]

Answer:

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Step-by-step explanation:

<u>Let the number be x:</u>

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It is -4

5 0
3 years ago
Whats the error?Jonah says a common denominator for 3/4 and 2/5 is 9.What is Jonahs error?
sammy [17]
In order to get the common denominator when adding fractions or subtracting fractions, you have to make sure  that the denominator of the two items are divisible by each other. In this case, 9 is not divisible by any of the given denominators which is 4 and 5. So in this case, the common denominator will have to be 20. 5 x 4 will equal to 20 and you will also multiply 3 x 5 to get the new numerator. After that, you will multiply 2 x 4 to get the new numerator of the other fraction. The new fractions will be 15/20 and 8/20. From there, you can add or subtract
6 0
3 years ago
A square can be. Rhombus, and figure X is a rhombus, so figure X must be a square. True or false
kvasek [131]
I have to go with True because a Rhombus is a Square. 
3 0
3 years ago
Read 2 more answers
(24xy^3-16x^2y^2+32x^2y)/8xy
Ahat [919]
(24xy^3-16x^2y^2+32x^2y)/8xy 

  <span><span>(<span><span>‌<span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>‌x</span>)</span><span>(y)</span></span><span>  =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>

4 0
3 years ago
Suppose you hit a fly ball with an initial upward velocity of 20 feet per second. Which of the following equations would be a re
baherus [9]
A=g≈-32

v=⌠a dt  since a≈-32

v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s

v=-32t+20

h=⌠v dt

h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height?  How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P

h=-16t^2+20t+3

Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:

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This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
3 0
3 years ago
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