Distance from J to F = b
D from F to K = a
a^2+b^2=JK^2
D from K to G = a
D from G to L = b
a^2+b^2=KL^2
D from L to H = b
D from H to M = a
a^2+b^2=LM^2
D from M to E = a
D from E to J = b
a^2+b^2=MJ^2
For each side, I used the Pythagorean theorem (a^2+b^2=c^2) to find the length. Since every side of the quadrilateral squared (aka to the power of two) equals a^2+b^2, every side squared equals each other. So JK^2=KL^2=LM^2=MJ^2. If you take the square root of each side of the equal signs, you’re left with JK=KL=LM=MJ. In order for a quadrilateral to be a rhombus, each side must be equivalent. Each side in this quadrilateral is equivalent, therefore it is a rhombus.
The 4th selection is appropriate.
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Desmos.com has a wonderful graphing calculator. They also have apps for Android and iOS phones and tablets. Of course, your TI-83/84 or equivalent will do this, too.
The answer is D. Most of the other answers are way to high to make sense
If we plug the values, we have
So, we have to solve the following equation:
So, when we impose 
, knowing the value of p, we have
And so the solution is
A₁ = 3
a₂ = 4.2
d = a₂ - a₁
= 4.2 - 3
= 1.2
a₉₈ = a₁ + d(n-1)
= 3 + 1.2(98-1)
= 3 + 1.2×97
= 3 + 116.4
= 119.4
