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andre [41]
3 years ago
5

Please answer this (I don’t know what else to put, it need 20 characters)

Mathematics
2 answers:
Vinvika [58]3 years ago
6 0

Answer:

15yd^2

Step-by-step explanation:

Triangle area formula is A = bh/2

A = 6*5/2

A = 30/2

A = 15

Best of Luck!

ExtremeBDS [4]3 years ago
4 0

Answer:

A = 15 yd^2

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh where b is the base and h is the height

A = 1/2 (6 * 5)

A = 1/2 (30)

A = 15 yd^2

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If a truck travels for 3 hours, how many miles will it travel? __ miles
Masja [62]

Answer:

You need to know the miles per hour they are going to find out this answer.

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%2045%2B%5Csqrt%2020-%5Csqrt5%5C%5C" id="TexFormula1" title="\sqrt 45+\sqrt 20-\sqrt5\\
allsm [11]

Answer:

\mathbf{4\sqrt{5}=\sqrt{80}}

Step-by-step explanation:

one thing you should keep in mind while solving questions related to surds.

  • \mathit{\sqrt{a^{4} \cdot b}=\sqrt{a^{2}} \cdot \sqrt{a^{2}} \cdot \sqrt{b}=a \cdot a \cdot \sqrt{b}=a^{2}\sqrt{b}}
  • \mathit{\sqrt{a^{5}}=\sqrt{a^{2}} \cdot \sqrt{a^{2}} \cdot \sqrt{a}=a \cdot a \cdot \sqrt{a}=a^{2} \cdot \sqrt{a}}

from the above examples you can see that if you have a square of any number inside a square root then you can remove the square root and the square from that number or in other words you can take the number out of the square root.

Similarly in this question:

\sqrt{45}=\sqrt{9 \cdot 5}=\sqrt{3^{2} \cdot 5}=\sqrt{3^{2}} \cdot \sqrt{5}=3\sqrt{5}

\sqrt{20}=\sqrt{4 \cdot 5}=\sqrt{2^{2} \cdot 5}=\sqrt{2^{2}} \cdot \sqrt{5}=2\sqrt{5}

∴ \sqrt{45}+\sqrt{20}-\sqrt{5}=3 \cdot \sqrt{5}+2 \cdot \sqrt{5}-1 \cdot \sqrt{5}

Now take out \sqrt{5} common from all the terms of the above expression.

\sqrt{5} \cdot (3+2-1)=\sqrt{5} \cdot 4=4\sqrt{5}

In this you can send the terms back inside the square root. For example:

  • \mathit{a=\sqrt{a^{2}}}
  • \mathit{a^{3}\sqrt{b}=a \cdot a \cdot a \cdot \sqrt{b}=\sqrt{a^{2}} \cdot \sqrt{a^{2}} \cdot \sqrt{a^{2}} \cdot \sqrt{b}=\sqrt{a^{2} \cdot a^{2} \cdot a^{2} \cdot b}=\sqrt{a^{6}b}}

Similarly 4\sqrt{5}=\sqrt{4^{2} \cdot 5}=\sqrt{16 \cdot 5}=\sqrt{\mathbf{80}}

8 0
3 years ago
Evaluate the expression show work. (4²- 8³)²+2³ <br><br>(Will receive 50 points)
Schach [20]

(4²-8³)²+2³ (16-512)²+2³ 496²+2³ 246,016+8 =246,024

5 0
3 years ago
0.737 ___ 0.708<br> 0.708 &gt; 0.737<br> 0.737 = 0.708<br> 0.737 &lt; 0.708<br> 0.737 &gt; 0.708
irina1246 [14]

Answer:

0.737>0.708

Step-by-step explanation:

it must me d because 0.737 is greater than 0.708 and it's the only true Statement

3 0
2 years ago
I will give brainiest to whoever answers correctly !!
Alchen [17]

Answer:

$80.75

Step-by-step explanation:

From the question, we are given the following parameters

Amount borrowed (principal)=$3800

Time=3 months =1/4 years

Rate = 8.5%

Required

Interest paid by the man

Using the simple interest formula;

SI= Principal*Rate*Time/100

SI=3800*8.5*0.25/100

SI=38*8.5*0.25

SI=$80.75

Hence the man paid $80.75 for the use of the money

PLEASE MARK ME AS BRAINLIEST

7 0
2 years ago
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