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zhuklara [117]
3 years ago
13

Solve this system of equations by graphing. First graph the equations, and then type the solution.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

The answer is below

Step-by-step explanation:

Solve this system of equations by graphing. First graph the equations, and then type the solution. y=2x+2 y=x–2

Solution:

The equation of a straight line is in the form y = mx + b, where m is the slope of the graph and b is the y intercept (value of y when x = 0). To graph the line, online geogebra graphing calculator was used for plotting the two graphs by writing the equation of the graphs.

After plotting the two graphs, the intersection of the two lines should be traced to get the x coordinate and y coordinate of the point. This point is the solution of the two graph equations, hence:

The solution = (-4, -6)

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Black_prince [1.1K]

Answer:

4

Step-by-step explanation:

you know what to do with a different person and you know what to do with 33rd grade and you know what to do with your child and your family

7 0
3 years ago
What is 463,462 rounded to the nearest ten thousand
kow [346]
460,000 :) hope this helps!!
6 0
3 years ago
Read 2 more answers
What are the values of x in the equation x^2 - 6x + 9 =25
never [62]
X² - 6x +9 =25
x² -6x -16 = 0
(x+2)(x-8) = 0
x+2 = 0 or x-8 = 0
the answer will be:
x = -2 or x = 8
6 0
3 years ago
Seven is not an example of____.
Ket [755]

Answer:

An expression

Step-by-step explanation:

Here is what I think it is. 7 is not an example of an expression because an expression is an equation without an equal sign. I believe that an expression has more than 1 number in it, so 7 is not an expression.

4 0
3 years ago
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Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
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