To solve the equation for x, first, we add 16 from both sides of the equation:
Now, we divide by 6:
Finally, we get that:
Answer:
Step-by-step explanation:
Since both lines intersect each other 3 units above the x-axis, the y-value of the point of intersection must be 3.
Looking at the options, (-3, 5), (3, -2) and (0, -3) are all invalid points.
Answer:
12 units
Step-by-step explanation:
Given that :
R(-3,2)
S(2,2)
T(2,-5).
The total length ;
Distance between two points : √[(x2 - x1)² + (y2 - y1)²]
Distance between R and S :
R = (-3,2)
S(2,2)
√[((2 - (-3))^2 + (2 - 2)^2]
Sqrt(5^2 + 0^2)
D1 = 5 units
Distance between S and T:
S(2,2)
T(2,-5).
D2 = √[(2 - 2)^2 + (-5 - 2)^2]
D2 = sqrt(0^2 + (-7)^2)
D2 = 7 units
Hence, total length = D1 + D2 = (5 + 7) = 12 units
x/3>-1
Isolate the x. Multiply 3 to both sides
(x/3)3 > -1(3)
x > -1(3)
x > -3
x > -3 is your answer
hope this helps
