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svetoff [14.1K]
3 years ago
13

8 cookies eaten in 2 minutes

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

wow so what's the question then

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If the length of the radius of a circle is doubled, how does that affect the circumference and area? Explain.
puteri [66]
The circumference is doubled since circumference is directly proportional to radius, and the area is quadrupled since it is directly proportional to the radius squared
8 0
3 years ago
Solve, and explain your answer step by step.<br><br> 12^8*7.96+4<br><br> Thanks.
Lostsunrise [7]

Answer:

3422654304.16

Step-by-step explanation:

Simplify exponents,

12^8*7.96+4

429981696*7.96+4

Multiply/divide left to right, then add/subtract.

429981696*7.96+4

3422654300.16+4

The answer would be 3422654304.16

Hope I helped.

8 0
3 years ago
1. Is the line that passes through the points A(0,1) and B(2,5) parallel to the line that passes through the points C(0,7) and D
kifflom [539]

You are correct that the slope of line AB is 2. To find the slope of the line CD, we can apply the slope formula again (like I assume you did with AB).

m=\frac{15-7}{4-0}=\boxed{2}

Therefore, since the slopes of lines AB and CD are equal, they are <u>parallel</u>

6 0
2 years ago
What is meant by the term the ???end of the Cold War???.
Neko [114]
Answer may be C hope helped
6 0
4 years ago
Find the values of x and y. Write your answers in simplest form
SCORPION-xisa [38]

Answer:

x =6

y=6\cdot \sqrt{2}

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios. There are six trigonometric ratios: sine, cosine, tangent, cosecant, secant, and cotangent.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Choosing any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image shows a right triangle where the angle of 45° has x as the opposite leg, 6 as the adjacent leg, and y as the hypotenuse. The trigonometric ratio that applies here is the cosine ratio, defined as:

\displaystyle \cos\theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 45^\circ=\frac{6}{y}

Solving for y:

\displaystyle y=\frac{6}{\cos 45^\circ}

\cos 45^\circ=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}

Substituting:

\displaystyle y=\frac{6}{\frac{1}{\sqrt{2}}}

y=6\cdot \sqrt{2}

Now use the tangent ratio:

\displaystyle \tan\theta=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 45^\circ=\frac{x}{6}

Solving for x:

x=6\cdot\tan 45^\circ

\tan 45^\circ=1

Substituting:

x=6\cdot 1

x =6

Answer:

x =6

y=6\cdot \sqrt{2}

6 0
3 years ago
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