Question

Mr. Garcia pays $834 for some model cars and model planes. Each model car costs $52 and each model plane costs $14 less than each model car. Mr. Garcia buys 3 more model planes than cars. How many model planes did he buy?

Answer 1

Answer:

Step-by-step explanation:

Given: Total Cost = $ 834

            Price of Car = $52

            Price of Plane = $14

Let, the number of model cars be x and model planes y.

⇒ 834 = 52x + 14y---------- (1)

Also, The number of model planes are 3 more than that of the model cars.

⇒y = x+3 ----------(2)

Substituting the value of y from (2) in (1)

    834 = 52x + 14(x+3)

⇒  834 = 52x + 14x +42

⇒834-42 = 66x

⇒66x = 792

⇒ x=12

Substituting the value of x in (2)

y = 12+3 = 15

Therefore, Mr. Garcia bought 15 model planes.