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disa [49]
2 years ago
5

A social club has 500 members. If 62% of members are male, what percentage are female?

Mathematics
2 answers:
marishachu [46]2 years ago
7 0

Answer:

310 members or 38% are female

Step-by-step explanation:

100% - 62%male = 38% female

or (62 × 500) ÷ 100 = 310 females

ki77a [65]2 years ago
4 0

Answer:

\huge\boxed{\sf 38\%}

Step-by-step explanation:

Total members = 500

Total percentage = 100%

Percentage of male members = 62%

<h3><u>Percentage of female members:</u></h3>

= 100% - male members

= 100% - 62%

= 38%

\rule[225]{225}{2}

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Solve the following System of Three Equations:<br> x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1
SashulF [63]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer:  {x = -3 , y = 4 , z = 0

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3 years ago
Max puts a stopper in the bathtub and turns on the faucet at t = 0.
Marysya12 [62]

Answer:

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Step-by-step explanation:

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Ivanshal [37]

Answer:

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Step-by-step explanation:

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3 years ago
(a^2 - b^2)/(2 + d^3)
Georgia [21]

Answer:

Solving the equation \frac{a^2-b^2}{2+d^3} by putting a=6, b=4 and d=1/2 we get \frac{160}{17}

Step-by-step explanation:

We are given formula: \frac{a^2-b^2}{2+d^3}

and values a=6, b=4 and d=1/2

We need to put the values of a, b and d in the given equation \frac{a^2-b^2}{2+d^3} and find their result

Putting values in the equation:

\frac{a^2-b^2}{2+d^3}\\=\frac{(6)^2-(4)^2}{2+(\frac{1}{2})^3}\\=\frac{36-16}{2+\frac{1}{8}}\\=\frac{20}{\frac{2*8+1}{8}}\\=\frac{20}{\frac{17}{8}}\\=\frac{20*8}{17}\\=\frac{160}{17}

So, solving the equation \frac{a^2-b^2}{2+d^3} by putting a=6, b=4 and d=1/2 we get \frac{160}{17}

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3 years ago
What is the salesperson's commission on a $600
Rama09 [41]

Answer:

it would be 180 dollars.

Step-by-step explanation:

as you do 30 percent of 600 dollars

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