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Alisiya [41]
3 years ago
5

Which transformation is not isometric?

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
A geometry transformation<span> is either rigid or non-rigid; another word for a rigid </span>transformation<span> is "</span>isometry<span>". An </span>isometry<span>, such as a rotation, translation, or reflection, does </span>not<span> change the size or shape of the figure.

The answer for the question is above is options A, B and C. I hope this helps.</span>
Vikentia [17]3 years ago
6 0
I hope this helps you



answer is D
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For each ordered pair in the table, how does the second number compare to the first number... can yall tell me I need to turn it
spayn [35]

Answer:

The first number in each ordered pair tells how far across the X line is to move. The second number in each ordered pair tells how far up or down the Y line is to move. The point where the X and Y lines cross is marked “0” on the graph. It is called the “origin,” and is the starting point for plotting points.

4 0
3 years ago
Part a: if angle a and angle b are vertical angles, what is the value of X?
Blizzard [7]

Answer:

a. x = 8

b. m<B = 140

Step-by-step explanation:

a.

m<A = m<B

40 = 5x

x = 8

b.

m<A + m<B = 180

m<B = 180 - m<A

m<B = 180 - 40

m<B = 140

7 0
3 years ago
Find the value of StartFraction partial derivative z Over partial derivative x EndFraction at the point​ (1,1,1) if the equation
scZoUnD [109]

Looks like the given curve is

5<em>xy</em> + <em>z</em>⁴<em>x</em> - 3<em>yz</em> = 3

Differentiate both sides with respect to <em>x</em> :

5<em>y</em> + 4<em>z</em>³<em>x</em> ∂<em>z</em>/∂<em>x</em> + <em>z</em>⁴ - 3<em>y</em> ∂<em>z</em>/∂<em>x</em> = 0

Solve for ∂<em>z</em>/∂<em>x</em> :

(4<em>z</em>³<em>x</em> - 3<em>y</em>) ∂<em>z</em>/∂<em>x</em> = - (5<em>y</em> + <em>z</em>⁴)

∂<em>z</em>/∂<em>x</em> = - (5<em>y</em> + <em>z</em>⁴) / (4<em>z</em>³<em>x</em> - 3<em>y</em>)

At the point (1, 1, 1), this derivative is

∂<em>z</em>/∂<em>x</em> (1, 1, 1) = - (5 + 1) / (4 - 3) = -6

4 0
3 years ago
Bodytemperatures ofhealthy koalasarenormally distributed with a mean of 35.6°C and a standard deviation of 1.3°C. a.What is the
Licemer1 [7]

Answer:

a

 P(X  < 35) =  32.3 \%

b

P(\= X  < 35) =  0.6 \%

Here the probability of koalas mean temperature being less than 35 °C is very small hence the koalas are not healthy

c

A potential confounding variable for this study is  the population of the koalas because in the first question the population was not taken into account and the probability was  P(X  < 35) =  32.3 \% but when the population was taken into account (i.e  n =  30) the probability became

P(\= X  < 35) =  0.6 \%  

Step-by-step explanation:

From the question we are told that

  The mean is  \mu =  35.6^oC

   The standard deviation is  s =  1.3^oC

   The sample size is  n = 30

Generally the  probability that a health koala has a body temperature less than 35.0°C is mathematically represented as

     P(X  < 35) =  P(\frac{X  - \mu }{s}  < \frac{35 - 35.6}{1.3} )

Here  (\frac{X  - \mu }{s} =  Z (The   \ standardized \  value \  of  \  X )

So

    P(X  < 35) =  P(Z < -0.46)

From the z-table  P(Z <  -0.46) =  0.323

So  

    P(X  < 35) =  0.323

Converting to percentage

      P(X  < 35) =  0.323  * 100

      P(X  < 35) =  32.3 \%

considering question b

The sample mean is  \= x =  35

Generally the standard error of the mean is mathematically represented as

   \sigma_{\= x} =  \frac{s}{\sqrt{n} }

=>  \sigma_{\= x} =  \frac{1.3}{\sqrt{30} }

=>  \sigma_{\= x} =  0.2373

Generally the probability of the mean body temperature of koalas being less than 35.0°C is mathematically represented as

 P(\= X  < 35) =  P(\frac{\= X  -  \mu  }{\sigma_{\= x }} <  \frac{35 -35.6}{0.2373 }  )

P(\= X  < 35) =  P(Z< -2.53  )

From the z-table  we have that

   P(Z< -2.53  ) =  0.006

So

 P(\= X  < 35) = 0.006 /tex] Converting to percentage        [tex]P(\= X  < 35) =   0.006  * 100

      P(\= X  < 35) =  0.6 \%

Here the probability of koalas mean temperature being less than 35 °C is very small hence the koalas are not healthy

A potential confounding variable for this study is  the population of the koalas because in the first question the population was not taken into account and the probability was  P(X  < 35) =  32.3 \% but when the population was taken into account (i.e  n =  30) the probability became

 P(\= X  < 35) =  0.6 \%  

4 0
4 years ago
Mr.still's class has musuc for 50 minutes and then independent reading for 20 mins Music start 8:30. What time does Mr.Still's c
stepan [7]
When they finish the independent reading it would be 9:40
7 0
3 years ago
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