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2 years ago

Why are experiments often performed in labs?

Physics

1 answer:

victus00 [196]2 years ago

6 0

Answer:

experiments provide course effective means of quantitative process kind of examing the bounds of theory is specially when the Nolan reality is important analysis

Explanation:

regardless of such topic the purpose of laboratory experiment is to test theory occurs by focusing on one server predictive elements of the theory is isolating the influence of elements on outcomes

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You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

3 years ago

A uniform brick of length 25 m is placed over

Harlamova29_29 [7]

The system of two rods will lie on the table as show in the figure

The center of first rod will lie exactly at the edge of first rod and then the center of mass of two combined rods will lie at the edge of the table.

So now the whole system will rest on the rod and it will not tipping off.

Since both rods are identical so we can say that the system will have its center of mass at the mid point on the line joining the two centers

So the value of x will be at mid point of line joining the two points on rod

$x = \frac{12.5}{2} = 6.25 cm$

So total length over the edge will be given as

$L = 6.25 cm + 12.5 cm = 18.75 cm$

3 0

3 years ago

A man drags a 71-kg crate across the floor at a constant velocity by pulling on a strap attached to the bottom of the crate. The

Flura [38]

Answer:

T = 540 N (to two significant digits)

Explanation:

Let the crate dimension L be from strap attachment to floor contact

Let T be the strap tension

sum moments about the floor contact point to zero

mg[½Lcos25] - Tsin61[Lcos25] + Tcos61[Lsin25] = 0

L is common to all terms, so divides out.

½(71)(9.8)cos25 = T(sin61cos25 - cos61sin25)

T = (71)(9.8)cos25 / (2(sin61cos25 - cos61sin25))

T = 536.428020...

7 0

3 years ago

A load of 36 N attached to a spring hanging

Annette [7]

Answer: 115.38N

Explanation:

Firstly, let's determine the constant.

Hooke's law was discovered by Robert Hooke in 1660.

Using hooke's law which states that provided the elastic limit of an elastic material is not exceeded, the force is equal to the extension applied provided all factors are kept constant.

Hooke's Law is a principle of physics that states that the force which is needed to extend or compress a spring by some distance is proportional to that distance

Therefore,

Force=kx

K= F/x

Where Force= 75m

x= 0.065m

K= 75/0.065m

K= 1153. 846N

We can use the constant to find the force when the distance that is stretched(x) is known.

Here

Force=kx

F= 1153.846 × 0.10

F= 115.38N

The force required to stretch it by this amount is 115.38N.

3 0

3 years ago

URGENT HELP WILL GIVE U BRAINLIEST

katrin [286]

Answer:

Explanation:

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7 0

3 years ago