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Kitty [74]
3 years ago
9

URGENT HELP WILL GIVE U BRAINLIEST

Physics
1 answer:
katrin [286]3 years ago
7 0

Answer:

<h3><u>1</u><u>2</u><u>9</u><u> </u><u>N</u></h3>

Explanation:

️️️️️️️️️️️️㊗️㊙️️️

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Gabriel is performing an experiment in which he is measuring the energy and work being done by a ball rolling down a hill. Which
melamori03 [73]

Answer:

They will both be recorded in Joules

Explanation:

- The energy of an object refers in general to the mechanical energy of the object, which is the sum of its kinetic energy (KE), which is the energy of motion, and of its potential energy (PE), which is the energy due to its position above the ground:

E=PE+KE

- The work done by an object is equal to the product between the force exerted by the object, F, and the displacement, d:

W=Fd (1)

The SI units of the energy is the Joules, J. The basic equivalence with SI units can be seen from the definition of kinetic energy:

KE=\frac{1}{2}mv^2

where

m is the mass, measured in kilograms (kg)

v is the speed, measured in meters per second (m/s)

So we have, since the speed is squared

1 J = 1 kg\cdot \frac{m^2}{s^2}

Now we can check from eq.(1) that the work as the same units. In fact, the force is measured in Newtons (N), and we know that force is equal to mass times acceleration, so we have:

1 N = 1 kg \cdot \frac{m}{s^2}

Distance is measured in meters (m), so the work is measured in

[W]=[kg \cdot \frac{m}{s^2}][m]=[kg\cdot \frac{m^2}{s^2}]

Which corresponds to the definition of Joule. Therefore, both energy and work are measured in Joules.

6 0
3 years ago
Read 2 more answers
A and B, move toward one another. Object A has twice the mass and half the speed of object B. Which of the following describes t
BARSIC [14]

Answer:D

Explanation:

Given

mass of A is twice the mass of B half the velocity of B

Suppose F_a and F_b be the average force exerted on A and B respectively

and According to Newton third law of motion Force on the body A is equal to Force on body B but opposite in direction as they are action and reaction force.

Thus F_a=-F_b  and option d is correct

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Chuge%20%5Crm%E0%BC%86%20question%20%E0%BC%84" id="TexFormula1" title=" \huge \rm༆ questi
kozerog [31]

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

5 0
3 years ago
Which statement best describes perigee?
algol13
<span>
A. The closet point in the Moon's orbit to Earth . . . . . perigee

B. The farthest point in the Moon's orbit to Earth . . . . . apogee

C. The Sun's orbit that is closest to the Moon . . . . . a meaningless description

D. The closest point in Earth's orbit of the Sun . . . . . perihelion

--  The farthest point in Earth's orbit of the Sun . . . . . aphelion
 </span>
7 0
4 years ago
Change in velocity from 2 to -3
Alecsey [184]

Velocity units =m/s

Acceleration is the rate of change of velocity

a =timechange in velocity

Therefore SI units of acceleration is ms−1/s=s2m

5 0
3 years ago
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