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Aloiza [94]
2 years ago
7

To prove that δdef ≅ δdgf by sas, what additional information is needed? ∠def ≅ ∠ dgf ∠dfe ≅ ∠ dfg de ≅ dg dg ≅ gf.

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0

Reflection:

Reflection is a type of rigid transformation which requires the turning of an object, shape or figure about a reference point or line. Therefore, the needed additional information is ∠DFE ≅ ∠ DFG.

Reflection implies turning the given triangle DEF about its side DF, so as to produce an image with the same dimensions but different orientation.

The required proof by Side-Angle-Side (SAS) implies that the relations will be in respect of two of its sides and their included angle.

So According to the above statement,

GF ≅ FE (: given)

DF is the common side to triangles DEF and DFG.

DFG is the included side.

Thus ∠DFE ≅ ∠ DFG (Side-Angle-Side postulate, SAS)

Learn more about Reflection on:

brainly.com/question/26494295

#SPJ4

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The larger number is 18 more than twice the smaller. If the sum of the two numbers is 93, find
Zigmanuir [339]

Answer:

The smaller is 25

the larger is 68

8 0
3 years ago
Which of the following statements does NOT adequately describe a developmental progression?
Artyom0805 [142]

The statement which does not adequately describe a developmental progression is Choice C- A developmental progression is a skill check- list that four-years- olds must master to be prepared for kindergarten.

<h3>What is developmental progression?</h3>

The Developmental Progression of Functional Skills is a concept which describes the child's growth in which case, the child's develops relationship with family members and a sense of self in the process and this concept in discuss is not limited to four-year olds.

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6 0
1 year ago
GUYS HELP ME PLS. Tina is standing at the bottom of a hill. Matt is standing on the hill so that when Tina's line of sight is
Pie

Answer:

71°

Step-by-step explanation:

The angle of elevation of the hill can be obtiaed using trigonometry :

Given

the opposite length = 14.5 feets

Adjacent = 5 feets

The angle of elevation vabnbe obtained using :

Tan θ = opposite / Adjacent

Where θ = angle of elevation

Tan θ = 14.5 / 5

Tan θ = 2.9

θ = tan^-1(2.9)

θ = 70.97 = 71°

3 0
3 years ago
Which is the graph of x Greater-than-or-equal-to 98.6? A number line going from 95 to 103. A closed circle is at 98.6. Everythin
Afina-wow [57]

Answer:

The correct option is;

A. A number line that goes from 95 to 103. A closed circle is at 98.6. Everything to the right is shaded.

Step-by-step explanation:

To represent x greater-than-or-equal-to 98.6 on the number line we note that an open circle stands for either a less than or a greater than, while an open circle stands for either less than or equal to or greater than or equal to

The correct way to represent x greater than or equal to 98.6 on the number line, we indicate the point 98.6 with a closed circle and we shade everything in the region of the solution which is to the right of the closed circle

Therefore the correct option is A. A number line that goes from 95 to 103. A closed circle at is at 98.6. Everyting to the right is shaded.

4 0
3 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
3 years ago
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