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Radda [10]
4 years ago
14

Six machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 2

7 hours to fill a certain production order, how many fewer hours does it take all six machines, operating simultaneously, to fill the same production order?A: 9B: 12C: 16D: 18E: 24
Mathematics
1 answer:
andreyandreev [35.5K]4 years ago
7 0

Answer:

A) 9

Step-by-step explanation:

No. of hours required: 4×27 = 108

If 6 machines working:

108÷6 = 18 hours

27 - 18 = 9 hours fewer

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A fish is 12 meters below the surface of the ocean. Its elevation is -12m. A sea bird is 28 meters above the surface of the ocea
babunello [35]

Answer:

40

Step-by-step explanation:

28+12= 40

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4 0
3 years ago
Solve by substitution
Hunter-Best [27]

Answer:

A

Step-by-step explanation:

y = -9 ------(1)

9x -4y = -9 -------(2)

substitute (1) into (2)

9x - 4 (-9) = -9

9x = - 45

x = -5

there you go, x = -5 and y = -9

so. (-5 , -9 )

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7 0
3 years ago
For a party, you buy 4 3/8 lbs of salt water taffy. If 150 people are attending, how much salt water taffy does each person get?
babymother [125]

Answer:

Step-by-step explanation

150 divided by 4 3/8 = 34.2

6 0
3 years ago
Having problems with this, please help.<br>And don’t know where to start.
rodikova [14]

Answer:

Use the pythagorean theorem to solve the equations. If you aren't solving for c, manipulate the equation to solve for whichever side you are solving for.

4 0
3 years ago
Read 2 more answers
A) how many men have a waist measurement of more than 85 cm
KATRIN_1 [288]

Answer:

(a)29

(b)91cm

(c)13cm

Step-by-step explanation:

(a)From the graph, 11 men have a waist measurement of 85cm and below.

Since the cumulative frequency is 40

Number of men who have a waist measurement of more than 85 cm

=40-11\\=29

(b)Median

\text{Median}=\dfrac{N}{2}\\N=40\\Median=\dfrac{40}{2}=20th$ item

Tracing 20 from the y-axis to the x-axis, the median waist measurement is 91cm.

(c)Interquartile Range

Interquartile Range = Q_3-Q_1

Q_1=\dfrac{N}{4}=\dfrac{40}{4}=10th$ item

From the graph, at y=10, x=84 cm

Q_3=\dfrac{3N}{4}=\dfrac{3*40}{4}=30th$ item

From the graph, at y=30, x=97 cm

Therefore:

Interquartile Range=97-84=13cm

5 0
3 years ago
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