There are several ways you can solve this problem if you're trying to solve for m and n. You can substitute, or systems of equations. However, I'm going to use substitution:
2m + n = 0 => n = -2m
We can input that in for the other equation:
m + 2n = 3 now becomes: m + 2(-2m) = 3
Now we can solve:
m + 2(−2m) = 3
m + −4m = 3
(m + −4m) = 3 (Combine Like Terms)
−3m=3
m = -1
Now we can input that value in to solve for n:
We said that n = -2m, and m = -1, so n = -2(-1):Answer:
n = 2
Your final answer is m = -1, and n = 2, which can also be written as (m,n) = (-1,2)
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However, if you were solving for m+n:
You would add the two equations!:
2m + n = 0
m + 2n = 3
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3m + 3n = 3
Now, you can take 3 common:
3(m+n) = 3
m + n = 1
Your final answer for what m + n equals 1!
Answer:
Quadrilateral ABCD is inscribed in a circle, then
A + C = 180
=> 2x + 9 + 3x + 1 = 180
=> 5x = 170
=> x = 34
=> A = 2 x 34 + 9 = 77 deg
Hope this helps!
:)
Answer: ![\sqrt[5]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%7D)
I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"
The rule I'm using is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
and the more general rule we could use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.
Answer:
Ok so the first one is right and the second one is right for the first question
For the second Question your also right
Step-by-step explanation:
Question 3
12/7 is greater than 6/13 and it's asking what numbers would be incorrect meaning less than 6/13 (unmark 12/7)
1/10 is correct since 6/13 is greater than 3 / 65 (It's what you get when you multiple 1/10 with 6/13)
Unmark 4/3
Unmark 3
and 13/13 is just equal to 6/13 (leave unmarked)
Question 4
I don't know kiddo it's been a while
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2/3 of pizza would be the answer
