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Yakvenalex [24]
2 years ago
14

Solve this trigonometry question, please by an easy method.​

Mathematics
2 answers:
Fynjy0 [20]2 years ago
8 0

Answer:

x = 7.41 (nearest hundredth)

y = 9.53 (nearest hundredth)

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

From inspection of the triangle:

  • \theta = 39°
  • O = 6
  • A = x
  • H = y

To find x, use the tan <u>trigonometric ratio</u>:

\implies \tan 39^{\circ}=\dfrac{6}{x}

\implies x=\dfrac{6}{\tan 39^{\circ}}

\implies x=7.409382939...

Therefore, x = 7.41 (nearest hundredth)

To find y, use the <u>sin trigonometric ratio</u>:

\implies \sin 39^{\circ}=\dfrac{6}{y}

\implies y=\dfrac{6}{\sin39^{\circ}}

\implies y=9.534094374...

Therefore, y = 9.53 (nearest hundredth)

Learn more about trigonometric ratios here:

brainly.com/question/27938163

brainly.com/question/27938731

podryga [215]2 years ago
7 0
  • tan39=6/x
  • x=6/tan39
  • x=7.4

And

  • sin39=6/y
  • y=6/sin39
  • y=9.5
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Answer:

R = 25

Step-by-step explanation:

Given

\frac{R}{5} - 6 = - 1

Multiply through by 5 to clear the fraction

R - 30 = - 5 ( add 30 to both sides )

R = 25

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3 years ago
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

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