Answer:
Short term memory or working memory
Explanation:
Woekin memory or short term memory refers to a limited-capacity store that not only retains information over the short term (maintenance), but also permits the performance of mental operations with the contents of this store (manipulation)
Answer:
Variable overhead efficiency variance= $558 favorable
Explanation:
Giving the following information:
Variable overhead 0.60 hours $ 3.10 per hour
Actual output 4,100 units
Actual direct labor-hours 2,280 hours
<u>To calculate the variable overhead efficiency variance, we need to use the following formula:</u>
Variable overhead efficiency variance= (Standard Quantity - Actual Quantity)*Standard rate
Variable overhead efficiency variance= (0.6*4,100 - 2,280)*3.10
Variable overhead efficiency variance= $558 favorable
Answer: (a) $197,500
(b) $ 189,500
Explanation:
Given : The marginal cost function : 
To find the cost function, we need to integrate the above function with respect to x.
Now, the additional cost incurred in dollars when production is increased from 100 units to 150 units will be:-
![\int^{150}_{100}\ C'(x)\ dx\\\\=\int^{150}_{100} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{150}_{100}\\\\=[4000(150)-\dfrac{0.4(150)^2}{2}-4000(100)+\dfrac{0.4(100)^2}{2}]\\\\=[600000-4500-400000+2000]\\\\=197500](https://tex.z-dn.net/?f=%5Cint%5E%7B150%7D_%7B100%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B150%7D_%7B100%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B150%7D_%7B100%7D%5C%5C%5C%5C%3D%5B4000%28150%29-%5Cdfrac%7B0.4%28150%29%5E2%7D%7B2%7D-4000%28100%29%2B%5Cdfrac%7B0.4%28100%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B600000-4500-400000%2B2000%5D%5C%5C%5C%5C%3D197500)
Hence, the additional cost incurred in dollars when production is increased from 100 units to 150 units= $197,500
Similarly, the additional cost incurred in dollars when production is increased from 500 units to 550 units :-
![\int^{550}_{500}\ C'(x)\ dx\\\\=\int^{550}_{500} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{550}_{500}\\\\=[4000(550)-\dfrac{0.4(550)^2}{2}-4000(500)+\dfrac{0.4(500)^2}{2}]\\\\=[2200000-60500-2000000+50000]\\\\=189,500](https://tex.z-dn.net/?f=%5Cint%5E%7B550%7D_%7B500%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B550%7D_%7B500%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B550%7D_%7B500%7D%5C%5C%5C%5C%3D%5B4000%28550%29-%5Cdfrac%7B0.4%28550%29%5E2%7D%7B2%7D-4000%28500%29%2B%5Cdfrac%7B0.4%28500%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B2200000-60500-2000000%2B50000%5D%5C%5C%5C%5C%3D189%2C500)
Hence, the additional cost incurred in dollars when production is increased from 500 units to 550 units = $ 189,500
Answer:
7,000 units
Explanation:
Calculation for the number of units set forth in the production budget, representing total production for the current period
Using this formula
Number of units =Current period +Ending inventory - Beginning inventory
Where,
Current period =7,000 units
Ending inventory=400 units
Beginning inventory =400 units
Let make plug in the formula above
Number of units =7,000 units + 400 units-400 units
Number of units =7,000 units
Therefore the Number of units will be 7,000 units
