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Aleksandr [31]
2 years ago
13

Simplify cube root of 5 over fourth root of 5 . (5 points) 5 to the power of 1 over 4 5 to the power of 1 over 12 5 to the power

of 7 over 12 5 to the power of 4 over 3
Mathematics
1 answer:
babymother [125]2 years ago
4 0

Answer:

{5}^{ \frac{1}{12} }  =  \sqrt[12]{5}

Step-by-step explanation:

\frac{ \sqrt[3]{5} }{ \sqrt[4]{5} }  =  {5}^{ \frac{1}{3} }  \div  {5}^{ \frac{1}{4} }  =  {5}^{ \frac{4}{12} }  \div {5}^{ \frac{3}{12} }  =  {5}^{ \frac{1}{12} }  =  \sqrt[12]{5}

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What is cos 45°?<br><br>A. 1<br>B. 1/sqrt of 2
Damm [24]
Cos 45 is option B! :)
8 0
4 years ago
How do i write 5,972,000,000,000,000,000,000,000kg in Scientific Notation
never [62]
In order to write this in scientific notation, we must move the decimal from the beginning all the way to between the 5 and the 9
Note: you can move the decimal anywhere you want but typically scientific notation will have the decimal in between the first and second digit.

Since we move the decimal 24 digits to the right, our answer will be

5.972 * 10^24
or
5.972E24

Hope this helps!!
8 0
3 years ago
Read 2 more answers
If U = the set of odd natural numbers and B = {13, 15, 17, 19, 21, 23, . . .}, find B′.
Yuki888 [10]

Answer:

{1,3,5,7,9,11}

Step-by-step explanation:

B' stands for the complement of B.

B' means set elements in the universe that aren't in B.

Here is the universe:

U={1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,...}

(The dots mean it continues with that pattern forever and ever.)

And the elements we taking out:

B={13,15,17,19,21,23,...}

So we taking out the odd numbers from U that are odd and greater than or equal to 13. (The dots mean it continues with that pattern forever and ever.)

So B' is the set of natural odd numbers that are less than 13:

{1,3,5,7,9,11}

8 0
3 years ago
Read 2 more answers
What expression is equivalent to (1/16)^-4
otez555 [7]

16^4  Hope this helps.

7 0
3 years ago
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LA DISTANCIA ENTRE LA TIERRA YLA LUNA ES DE 384 392 KM. LOS AUSTRONAUTAS DE LA APOLO XL SALIERON EL 16 DE JULIO DE 1969 DESDE EL
KengaRu [80]

Complete question :

la distancia entre la tierra y la luna es de 384 392 km. Los astronautas de la Apolo XL salieron el 16 de julio de 1969 desde el Centro Espacial Kennedy y al alcanzaron la orbita el 19 de julio de 1969. Suponiendo que cada dia recorrieron la misma cantidad de kilometros cuantos kilometros recorrieron por dia

Responder:

128130,66 kilometros

Explicación paso a paso:

Dado que:

Distancia entre la tierra y la luna = 384,392 km

Tiempo empleado = (19 de julio - 16 de julio) mismo año = 3 días

Velocidad = distancia / tiempo

El tiempo empleado es (3 * 24) = 72 horas

Por lo tanto,

velocidad = 384,392 / 72

= 5338,7777 kilómetros por hora

Dado que se supone que la distancia recorrida diariamente es la misma m:

El número de kilómetros recorridos por día:

5338,7777 kilómetros por hora * 24

= 128130,66 kilometros

4 0
3 years ago
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